# Tables: Exercise-4

#### Overview:

 Questions and Answers Type: MCQ (Multiple Choice Questions). Main Topic: Data Interpretation. Data Interpretation Sub-topic: Tables Questions and Answers. Number of Questions: 5 Questions with Solutions.

Directions: Study the following table carefully and answer the questions given below it.

Percent profit earned by six different companies over the years. 1. If the profit earned by company B in the year 2012 was Rs.5 lacs, what was the income of the company in that year?

1. Rs56.26 lacs
2. Rs52.46 lacs
3. Rs48.12 lacs
4. Rs46.67 lacs

Answer: (d) Rs46.67 lacs

Solution: Let the expenditure of the company B in the year 2012 = Rs. X lacs

then, $$\frac{5}{X} \times 100 = 12$$ $$X = \frac{5 \times 100}{12}$$ $$X = 41.67 \ lacs$$ Hence, the income of the company B in the year 2012, $$= (5 + 41.67) \ lacs$$ $$= Rs46.67 \ lacs$$

1. What is the percentage rise in percent profit of company E in the year 2015 from the year 2010?

1. 100%
2. 60%
3. 50%
4. 30%

Solution: Required percentage increase, $$= \frac{16 - 8}{8} \times 100$$ $$= 100 \ \%$$

1. If the profit earned by the company A in the year 2013 was Rs.2 lacs, what was its expenditure in that year?

1. Rs12.25 lacs
2. Rs16.12 lacs
3. Rs18.18 lacs
4. Rs.20.32 lacs

Answer: (c) Rs18.18 lacs

Solution: Let the expenditure of the company A in the year 2013 = Rs.X lacs

then, $$\frac{2}{X} \times 100 = 11$$ $$X = \frac{2 \times 100}{11}$$ $$X = Rs18.18 \ lacs$$

1. What was the average percent profit of company C over all the year together?

1. 10.17%
2. 12.22%
3. 15.32%
4. 16.25%

Solution: The average percent profit of company C over all the year together, $$= \frac{8 + 9 + 10 + 15 + 12 + 7}{6}$$ $$= 10.17 \ \%$$

1. What is the difference between the percent profit earned by company D in the year 2010 and the average percent profit earned by the remaining companies together in that year?

1. 1.2%
2. 1.6%
3. 1.8%
4. 1.9%

Solution: Required difference, $$= 12 - \left[\frac{10 + 15 + 8 + 8 + 11}{5}\right]$$ $$= 12 - 10.4$$ $$= 1.6 \ \%$$