Questions and Answers Type: | MCQ (Multiple Choice Questions). |

Main Topic: | Data Interpretation. |

Data Interpretation Sub-topic: | Tables Questions and Answers. |

Number of Questions: | 5 Questions with Solutions. |

**Directions:** Study the following table carefully and answer the questions given below it.

**The percentage of marks obtained by six students in five different subjects in an examination.**

- How many students obtained 75% and above marks in all the subjects?
- 1
- 2
- 3
- 4

Answer: (c) 3

Solution: The students B, D, and F obtained 75% and above in all the subjects.

Solution: The students B, D, and F obtained 75% and above in all the subjects.

- What are the average marks obtained by all the students in English?
- 118.75
- 120.25
- 122.17
- 125.65

Answer: (a) 118.75

Solution: The marks obtained by students in English.$$ A = \frac{80}{100} \times 150 $$ $$ = 120 $$ $$ B = \frac{90}{100} \times 150 $$ $$ = 135 $$ $$ C = \frac{75}{100} \times 150 $$ $$ = 112.5 $$ $$ D = \frac{85}{100} \times 150 $$ $$ = 127.5 $$ $$ E = \frac{70}{100} \times 150 $$ $$ = 105 $$ $$ F = \frac{75}{100} \times 150 $$ $$ = 112.5 $$ Total marks obtained by all the students together in English = 120 + 135 + 112.5 + 127.5 + 105 + 112.5 = 712.5

Required Average $$ = \frac{712.5}{6} $$ $$ = 118.75 $$

Solution: The marks obtained by students in English.$$ A = \frac{80}{100} \times 150 $$ $$ = 120 $$ $$ B = \frac{90}{100} \times 150 $$ $$ = 135 $$ $$ C = \frac{75}{100} \times 150 $$ $$ = 112.5 $$ $$ D = \frac{85}{100} \times 150 $$ $$ = 127.5 $$ $$ E = \frac{70}{100} \times 150 $$ $$ = 105 $$ $$ F = \frac{75}{100} \times 150 $$ $$ = 112.5 $$ Total marks obtained by all the students together in English = 120 + 135 + 112.5 + 127.5 + 105 + 112.5 = 712.5

Required Average $$ = \frac{712.5}{6} $$ $$ = 118.75 $$

- What is the approximate overall percentage of student D?
- 76 %
- 78 %
- 80 %
- 82 %

Answer: (d) 82 %

Solution: Marks obtained by student D in different subjects. $$ History = \frac{85}{100} \times 100 $$ $$ = 85 $$ $$ English = \frac{85}{100} \times 150 $$ $$ = 127.5 $$ $$ Hindi = \frac{80}{100} \times 150 $$ $$ = 120 $$ $$ Computer = \frac{85}{100} \times 100 $$ $$ = 85 $$ $$ Geography = \frac{75}{100} \times 100 $$ $$ = 75 $$ Total marks obtained by D in all the subjects together = 85 + 127.5 + 120 + 85 + 75 = 492.5

Total maximum marks for all the subjects together = 100 + 150 + 150 + 100 + 100 = 600

Hence the overall percentage of student D $$ = \frac{492.5}{600} \times 100 $$ $$ = 82.08 \ \% $$ $$ \approx 82 \ \% $$

Solution: Marks obtained by student D in different subjects. $$ History = \frac{85}{100} \times 100 $$ $$ = 85 $$ $$ English = \frac{85}{100} \times 150 $$ $$ = 127.5 $$ $$ Hindi = \frac{80}{100} \times 150 $$ $$ = 120 $$ $$ Computer = \frac{85}{100} \times 100 $$ $$ = 85 $$ $$ Geography = \frac{75}{100} \times 100 $$ $$ = 75 $$ Total marks obtained by D in all the subjects together = 85 + 127.5 + 120 + 85 + 75 = 492.5

Total maximum marks for all the subjects together = 100 + 150 + 150 + 100 + 100 = 600

Hence the overall percentage of student D $$ = \frac{492.5}{600} \times 100 $$ $$ = 82.08 \ \% $$ $$ \approx 82 \ \% $$

- What were the total marks obtained by student A in all the subjects together?
- 490
- 470
- 465
- 760

Answer: (b) 470

Solution: Marks obtained by student A in different subjects.$$ History = \frac{75}{100} \times 100 $$ $$ = 75 $$ $$ English = \frac{80}{100} \times 150 $$ $$ = 120 $$ $$ Hindi = \frac{70}{100} \times 150 $$ $$ = 105 $$ $$ Computer = \frac{80}{100} \times 100 $$ $$ = 80 $$ $$ Geography = \frac{90}{100} \times 100 $$ $$ = 90 $$ Hence total marks obtained by student A in all the subjects together = 75 + 120 + 105 + 80 + 90 = 470 Marks.

Solution: Marks obtained by student A in different subjects.$$ History = \frac{75}{100} \times 100 $$ $$ = 75 $$ $$ English = \frac{80}{100} \times 150 $$ $$ = 120 $$ $$ Hindi = \frac{70}{100} \times 150 $$ $$ = 105 $$ $$ Computer = \frac{80}{100} \times 100 $$ $$ = 80 $$ $$ Geography = \frac{90}{100} \times 100 $$ $$ = 90 $$ Hence total marks obtained by student A in all the subjects together = 75 + 120 + 105 + 80 + 90 = 470 Marks.

- What is the ratio between the marks obtained by student A in English to the marks obtained by the student E in the same subject?
- 8 : 7
- 7 : 8
- 7 : 9
- 9 : 7

Answer: (a) 8 : 7

Solution: Marks obtained by student A in English.$$ = \frac{80}{100} \times 150 $$ $$ = 120 $$ Marks obtained by student E in English.$$ = \frac{70}{100} \times 150 $$ $$ = 105 $$ Hence required ratio $$ = \frac{120}{105} $$ $$ = \frac{8}{7} $$ $$ = 8 : 7 $$

Solution: Marks obtained by student A in English.$$ = \frac{80}{100} \times 150 $$ $$ = 120 $$ Marks obtained by student E in English.$$ = \frac{70}{100} \times 150 $$ $$ = 105 $$ Hence required ratio $$ = \frac{120}{105} $$ $$ = \frac{8}{7} $$ $$ = 8 : 7 $$