Tables: Exercise-10


Overview:


Questions and Answers Type:MCQ (Multiple Choice Questions).
Main Topic:Data Interpretation.
Data Interpretation Sub-topic:Tables Questions and Answers.
Number of Questions:5 Questions with Solutions.

Directions: Study the following table carefully and answer the questions given below it.


The percentage of marks obtained by six students in five different subjects in an examination.


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  1. How many students obtained 75% and above marks in all the subjects?

    1. 1
    2. 2
    3. 3
    4. 4


Answer: (c) 3

Solution: The students B, D, and F obtained 75% and above in all the subjects.

  1. What are the average marks obtained by all the students in English?

    1. 118.75
    2. 120.25
    3. 122.17
    4. 125.65


Answer: (a) 118.75

Solution: The marks obtained by students in English.$$ A = \frac{80}{100} \times 150 $$ $$ = 120 $$ $$ B = \frac{90}{100} \times 150 $$ $$ = 135 $$ $$ C = \frac{75}{100} \times 150 $$ $$ = 112.5 $$ $$ D = \frac{85}{100} \times 150 $$ $$ = 127.5 $$ $$ E = \frac{70}{100} \times 150 $$ $$ = 105 $$ $$ F = \frac{75}{100} \times 150 $$ $$ = 112.5 $$ Total marks obtained by all the students together in English = 120 + 135 + 112.5 + 127.5 + 105 + 112.5 = 712.5

Required Average $$ = \frac{712.5}{6} $$ $$ = 118.75 $$

  1. What is the approximate overall percentage of student D?

    1. 76 %
    2. 78 %
    3. 80 %
    4. 82 %


Answer: (d) 82 %

Solution: Marks obtained by student D in different subjects. $$ History = \frac{85}{100} \times 100 $$ $$ = 85 $$ $$ English = \frac{85}{100} \times 150 $$ $$ = 127.5 $$ $$ Hindi = \frac{80}{100} \times 150 $$ $$ = 120 $$ $$ Computer = \frac{85}{100} \times 100 $$ $$ = 85 $$ $$ Geography = \frac{75}{100} \times 100 $$ $$ = 75 $$ Total marks obtained by D in all the subjects together = 85 + 127.5 + 120 + 85 + 75 = 492.5

Total maximum marks for all the subjects together = 100 + 150 + 150 + 100 + 100 = 600

Hence the overall percentage of student D $$ = \frac{492.5}{600} \times 100 $$ $$ = 82.08 \ \% $$ $$ \approx 82 \ \% $$

  1. What were the total marks obtained by student A in all the subjects together?

    1. 490
    2. 470
    3. 465
    4. 760


Answer: (b) 470

Solution: Marks obtained by student A in different subjects.$$ History = \frac{75}{100} \times 100 $$ $$ = 75 $$ $$ English = \frac{80}{100} \times 150 $$ $$ = 120 $$ $$ Hindi = \frac{70}{100} \times 150 $$ $$ = 105 $$ $$ Computer = \frac{80}{100} \times 100 $$ $$ = 80 $$ $$ Geography = \frac{90}{100} \times 100 $$ $$ = 90 $$ Hence total marks obtained by student A in all the subjects together = 75 + 120 + 105 + 80 + 90 = 470 Marks.

  1. What is the ratio between the marks obtained by student A in English to the marks obtained by the student E in the same subject?

    1. 8 : 7
    2. 7 : 8
    3. 7 : 9
    4. 9 : 7


Answer: (a) 8 : 7

Solution: Marks obtained by student A in English.$$ = \frac{80}{100} \times 150 $$ $$ = 120 $$ Marks obtained by student E in English.$$ = \frac{70}{100} \times 150 $$ $$ = 105 $$ Hence required ratio $$ = \frac{120}{105} $$ $$ = \frac{8}{7} $$ $$ = 8 : 7 $$