Tables: Exercise-3


Overview:


Questions and Answers Type:MCQ (Multiple Choice Questions).
Main Topic:Data Interpretation.
Data Interpretation Sub-topic:Tables Questions and Answers.
Number of Questions:5 Questions with Solutions.

Directions: Study the following table carefully and answer the questions given below it.


Data related to number of employees in five different organisations in January 2017.


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  1. The average number of science graduate employees and art graduate employees in company P was 800. What is the total number of employees in company P?

    1. 3556
    2. 3568
    3. 3572
    4. 3576


Answer: (a) 3556

Solution: Total number of science and art graduate employees in company P, $$ = 800 \times 2 = 1600 $$ from the table, $$ 45 \ \% = 1600 $$ then, $$ 100 \ \% = \frac{1600}{45} \times 100 $$ $$ = 3555.56 \approx 3556 $$

  1. Total number of employees in company T was two times the total number of employees in company Q. If the difference between number of art graduate employees in company T and that in company Q was 500, what was the total number of employees in company Q?

    1. 3333
    2. 3432
    3. 3533
    4. 4333


Answer: (a) 3333

Solution: Let total employees in company Q = X

then total employees in company T = 2X

Now thw difference between art graduate employees in company T and that in company Q, $$ \left[(100 - 50 - 30) \ \% \ of \ 2X\right] \\ - \left[25 \ \% \ of \ X\right] = 500 $$ $$ \frac{20 \times 2X}{100} - \frac{25 \times X}{100} = 500 $$ $$ = \frac{40X - 25X}{100} = 500 $$ $$ 15X = 500 $$ $$ X = 3333.34 \approx 3333 $$ Hence, total number of employees in company Q = 3333

  1. If the respective ratio between number of engineering graduate employees and art graduate employees in company S was 5:7, what was the number of engineering graduate employees in company S?

    1. 350
    2. 400
    3. 450
    4. 550


Answer: (c) 450

Solution: Ratio of engineering graduates and art graduates in company S = 5:7

Total number of engineering graduates and art graduates in company , $$ = \left[20 \ \% \ of \ 1800\right] \\ + \left[(100 - 40 - 20) \ \% \ of \ 1800\right] $$ $$ = \frac{20 \times 1800}{100} + \frac{40 \times 1800}{100} $$ $$ = 360 + 720 = 1080 $$ Hence, the number of engineering graduates in company S, $$ = \frac{5}{12} \times 100 $$ $$ = 450 $$

  1. The total number of employees in company R increased by 20% from January 2017 to January 2018. If 50% of the total number of employees in company R in January 2018 were art graduates, what was the number of art graduate employees in company R in January 2018?

    1. 700
    2. 900
    3. 1100
    4. 1200


Answer: (b) 900

Solution: Total number of employees in company R in 2017, $$ = \frac{1500 \times 120}{100} $$ $$ = 1800 $$ Hence, art graduate employees in company R in January 2018, $$ = 50 \ \% \ of \ 1800 $$ $$ = \frac{50 \times 1800}{100} = 900 $$

  1. What was the difference between number of engineering graduate employees and science graduate employees in company R?

    1. 110
    2. 120
    3. 150
    4. 180


Answer: (c) 150

Solution: Number of engineering graduates in company R, $$ = 40 \ \% \ of \ 1500 $$ $$ = \frac{40 \times 1500}{100} = 600 $$ Number of science graduates in company R, $$ = (100 - 30 - 40) \ \% \ of \ 1500 $$ $$ = 30 \ \% \ of \ 1500 $$ $$ = \frac{30 \times 1500}{100} = 450 $$ Hence, Required difference, $$ = 600 - 450 = 150 $$