Questions and Answers Type: | MCQ (Multiple Choice Questions). |

Main Topic: | Quantitative Aptitude. |

Quantitative Aptitude Sub-topic: | Number System Aptitude Questions and Answers. |

Number of Questions: | 10 Questions with Solutions. |

- Find the difference between the local value and the face value of digit 4 in numeral 23465?
- 396
- 404
- 0
- 800

Answer: (a) 396

Solution: Place vaue or local value of digit 4 in 23465 = 400

And the face value of digit 4 in 23465 = 4

Hence the required difference. $$ = 400 - 4 $$ $$ = 396 $$

Solution: Place vaue or local value of digit 4 in 23465 = 400

And the face value of digit 4 in 23465 = 4

Hence the required difference. $$ = 400 - 4 $$ $$ = 396 $$

- Find the product of the place value of two 7s in the numeral 410,720,475?
- 700,070
- 699,930
- 49,000,000
- 4,900,000

Answer: (c) 49,000,000

Solution: Place value of 7 in tenth place = 70

And the place value of 7 in place of hundred thousand place = 700,000

Hance required product. $$ = 70 \times 700,000 $$ $$ = 49,000,000 $$

Solution: Place value of 7 in tenth place = 70

And the place value of 7 in place of hundred thousand place = 700,000

Hance required product. $$ = 70 \times 700,000 $$ $$ = 49,000,000 $$

- Find the sum of the place value of digit 3 in the numeral 43502 and place value of digit 4 in the numeral 604378?
- 12,000,000
- 7,000
- 1,000
- 4,003

Answer: (b) 7,000

Solution: Place value of digit 3 in 43502 = 3,000

Place value of digit 4 in 604378 = 4,000

Hence required sum. $$ = 3,000 + 4,000 $$ $$ = 7,000 $$

Solution: Place value of digit 3 in 43502 = 3,000

Place value of digit 4 in 604378 = 4,000

Hence required sum. $$ = 3,000 + 4,000 $$ $$ = 7,000 $$

- Find the product of the face value of digit 5 and place value of digit 6 in the numeral 7256013?
- 3,000
- 6,005
- 300,000
- 30,000

Answer: (d) 30,000

Solution: Face value of digit 5 in 7256013 = 5

Place value of digit 6 in 7256013 = 6,000

Hence required product. $$ = 5 \times 6,000 $$ $$ = 30,000 $$

Solution: Face value of digit 5 in 7256013 = 5

Place value of digit 6 in 7256013 = 6,000

Hence required product. $$ = 5 \times 6,000 $$ $$ = 30,000 $$

- Find the sum and difference of the place value of digit 5 and face value of digit 3 in the numeral 2,503,681?
- Sum = 500,003, Difference = 499,997
- Sum = 499,997, Difference = 500,003
- Sum = 500,000, Difference = 499,999
- Sum = 500,006, Difference = 499,994

Answer: (a) Sum = 500,003, Difference = 499,997

Solution: Place value of digit 5 in 2503681 = 500,000

Face value of digit 3 in 2503681 = 3

Hence required sum. $$ = 500,000 + 3 $$ $$ = 500,003 $$ and the required difference. $$ = 500,000 - 3 $$ $$ = 499,997 $$

Solution: Place value of digit 5 in 2503681 = 500,000

Face value of digit 3 in 2503681 = 3

Hence required sum. $$ = 500,000 + 3 $$ $$ = 500,003 $$ and the required difference. $$ = 500,000 - 3 $$ $$ = 499,997 $$

Lec 1: Introduction to Number System
Lec 2: Factors of Composite Number
Questions and Answers-1
Lec 3: Basic Remainder Theorem
Questions and Answers-2
Lec 4: Polynomial Remainder Theorem
Questions and Answers-3
Questions and Answers-4
Questions and Answers-5
Lec 5: LCM of Numbers
Questions and Answers-6
Lec 6: HCF of Numbers
Questions and Answers-7
Questions and Answers-8
Lec 7: Divisibility Rules of Numbers
Questions and Answers-9
Questions and Answers-10
Questions and Answers-11
Questions and Answers-12
Questions and Answers-13
Questions and Answers-14
Questions and Answers-15
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