# Number System Aptitude Questions and Answers:

#### Overview:

 Questions and Answers Type: MCQ (Multiple Choice Questions). Main Topic: Quantitative Aptitude. Quantitative Aptitude Sub-topic: Number System Aptitude Questions and Answers. Number of Questions: 10 Questions with Solutions.

1. If $$\frac{3}{4}$$ th of $$\frac{2}{7}$$ th of a number is 34 then find the number?

1. 156.22
2. 158.67
3. 159.32
4. 162.53

Solution: Let the number is x then $$x \times \frac{3}{4} \times \frac{2}{7} = 34$$ $$\frac{3x}{14} = 34$$ $$x = \frac{34 \times 14}{3}$$ $$x = \frac{476}{3}$$ $$x = 158.67$$

1. If $$\frac{2}{5}$$ th of 80 is x then find the value of x?

1. 32
2. 23
3. 33
4. 22

Solution: According to the question $$\frac{2}{5} \times 80 = x$$ $$x = 32$$

1. If the fractions $$\frac{2}{5}$$, $$\frac{3}{5}$$, $$\frac{6}{7}$$, and $$\frac{2}{3}$$ are arranged in ascending order of their values. Which one will be in the second place?

1. $$\frac{2}{5}$$
2. $$\frac{3}{5}$$
3. $$\frac{6}{7}$$
4. $$\frac{2}{3}$$

Answer: (b) $$\frac{3}{5}$$

Solution: $$\frac{2}{5} = 0.4$$ $$\frac{3}{5} = 0.6$$ $$\frac{6}{7} = 0.857$$ $$\frac{2}{3} = 0.67$$ By writing the values in ascending order $$\frac{2}{5}, \frac{3}{5}, \frac{2}{3}, \frac{6}{7}$$ Hence $$\frac{3}{5}$$ will be on second place.

1. If the fractions $$\frac{3}{8}$$, $$\frac{2}{9}$$, $$\frac{4}{7}$$, and $$\frac{5}{12}$$ are arranged in descending order of their values. Which one will be in the third place?

1. $$\frac{3}{8}$$
2. $$\frac{2}{9}$$
3. $$\frac{4}{7}$$
4. $$\frac{5}{12}$$

Answer: (a) $$\frac{3}{8}$$

Solution: $$\frac{3}{8} = 0.375$$ $$\frac{2}{9} = 0.23$$ $$\frac{4}{7} = 0.57$$ $$\frac{5}{12} = 0.4167$$ By writing the values in descending order $$\frac{4}{7}, \frac{5}{12}, \frac{3}{8}, \frac{2}{9}$$ Hence $$\frac{3}{8}$$ will be on third place.

1. I have some horses and pigeons. If the total number of animal-heads is 51 and the total number of feet is 178 then find how many pigeons I have?

1. 15
2. 14
3. 13
4. 12

Solution: Let I have x number of pigeons and y number of horses then $$x + y = 51....(1)$$ As pigeons have two feet each and horses have four feet each then $$2x + 4y = 178....(2)$$ by multiplying 4 with equation (1) $$4x + 4y = 204....(3)$$ by subtracting equation (2) from equation (3) $$4x + 4y - 2x - 4y = 26$$ $$2x = 26$$ $$x = 13$$ Hence I have 13 pigeons.