Questions and Answers Type: | MCQ (Multiple Choice Questions). |

Main Topic: | Quantitative Aptitude. |

Quantitative Aptitude Sub-topic: | Number System Aptitude Questions and Answers. |

Number of Questions: | 10 Questions with Solutions. |

- Find the factors of composite number \(500\)?
- \(12\)
- \(6\)
- \(9\)
- \(10\)

Answer: (a) \(12\)

Solution: \(500 = 2 \times 2 \times 5 \times 5 \times 5 = 2^2 \times 5^3\)

\(factors \ of \ composite \ number\)

\(= (2 + 1) \ (3 + 1) = 3 \times 4 = 12\)

Solution: \(500 = 2 \times 2 \times 5 \times 5 \times 5 = 2^2 \times 5^3\)

\(factors \ of \ composite \ number\)

\(= (2 + 1) \ (3 + 1) = 3 \times 4 = 12\)

- Find the factors of composite number \(300\)?
- \(12\)
- \(18\)
- \(14\)
- \(10\)

Answer: (b) \(18\)

Solution: \(300 = 2 \times 2 \times 3 \times 5 \times 5 = 2^2 \times 3^1 \times 5^2\)

\(factors \ of \ composite \ number\)

\(= (2 + 1) \ (1 + 1) \ (2 + 1) = 3 \times 2 \times 3 = 18\)

Solution: \(300 = 2 \times 2 \times 3 \times 5 \times 5 = 2^2 \times 3^1 \times 5^2\)

\(factors \ of \ composite \ number\)

\(= (2 + 1) \ (1 + 1) \ (2 + 1) = 3 \times 2 \times 3 = 18\)

- Find the factors of composite number \(700\)?
- \(16\)
- \(20\)
- \(19\)
- \(18\)

Answer: (d) \(18\)

Solution: \(700 = 2 \times 2 \times 5 \times 5 \times 7 = 2^2 \times 5^2 \times 7^1\)

\(factors \ of \ composite \ number\)

\(= (2 + 1) \ (2 + 1) \ (1 + 1) = 3 \times 3 \times 2 = 18\)

Solution: \(700 = 2 \times 2 \times 5 \times 5 \times 7 = 2^2 \times 5^2 \times 7^1\)

\(factors \ of \ composite \ number\)

\(= (2 + 1) \ (2 + 1) \ (1 + 1) = 3 \times 3 \times 2 = 18\)

- Find the factors of composite number \(450\)?
- \(18\)
- \(16\)
- \(19\)
- \(15\)

Answer: (a) \(18\)

Solution: \(450 = 2 \times 3 \times 3 \times 5 \times 5 = 2^1 \times 3^2 \times 5^2\)

\(factors \ of \ composite \ number\)

\(= (1 + 1) \ (2 + 1) \ (2 + 1) = 2 \times 3 \times 3 = 18\)

Solution: \(450 = 2 \times 3 \times 3 \times 5 \times 5 = 2^1 \times 3^2 \times 5^2\)

\(factors \ of \ composite \ number\)

\(= (1 + 1) \ (2 + 1) \ (2 + 1) = 2 \times 3 \times 3 = 18\)

- Find the factors of composite number \(600\)?
- \(20\)
- \(26\)
- \(24\)
- \(28\)

Answer: (c) \(24\)

Solution: \(600 = 2 \times 2 \times 2 \times 3 \times 5 \times 5 = 2^3 \times 3^1 \times 5^2\)

\(factors \ of \ composite \ number\)

\(= (3 + 1) \ (1 + 1) \ (2 + 1) = 4 \times 2 \times 3 = 24\)

Solution: \(600 = 2 \times 2 \times 2 \times 3 \times 5 \times 5 = 2^3 \times 3^1 \times 5^2\)

\(factors \ of \ composite \ number\)

\(= (3 + 1) \ (1 + 1) \ (2 + 1) = 4 \times 2 \times 3 = 24\)

- Find all the factors of composite number \(1610\)?
- \(15\)
- \(16\)
- \(18\)
- \(12\)

Answer: (b) \(16\)

Solution: \(1610 = 2 \times 5 \times 7 \times 23 = 2^1 \times 5^1 \times 7^1 \times 23^1\)

\(factors \ of \ composite \ number\)

\(= (1 + 1) \ (1 + 1) \ (1 + 1) \ (1 + 1)\)

\(= 2 \times 2 \times 2 \times 2 = 16\)

Solution: \(1610 = 2 \times 5 \times 7 \times 23 = 2^1 \times 5^1 \times 7^1 \times 23^1\)

\(factors \ of \ composite \ number\)

\(= (1 + 1) \ (1 + 1) \ (1 + 1) \ (1 + 1)\)

\(= 2 \times 2 \times 2 \times 2 = 16\)

- Find the factors of composite number \(1830\)?
- \(10\)
- \(14\)
- \(12\)
- \(16\)

Answer: (d) \(16\)

Solution: \(1830 = 2 \times 3 \times 5 \times 61 = 2^1 \times 3^1 \times 5^1 \times 61^1\)

\(factors \ of \ composite \ number\)

\(= (1 + 1) \ (1 + 1) \ (1 + 1) \ (1 + 1)\)

\(= 2 \times 2 \times 2 \times 2 = 16\)

Solution: \(1830 = 2 \times 3 \times 5 \times 61 = 2^1 \times 3^1 \times 5^1 \times 61^1\)

\(factors \ of \ composite \ number\)

\(= (1 + 1) \ (1 + 1) \ (1 + 1) \ (1 + 1)\)

\(= 2 \times 2 \times 2 \times 2 = 16\)

- Find the factors of composite number \(19\)?
- \(4\)
- \(3\)
- \(2\)
- \(1\)

Answer: (c) \(2\)

Solution: \(19\) is a prime number and any prime number have only two factors \(1\) and itself.

Solution: \(19\) is a prime number and any prime number have only two factors \(1\) and itself.

- Find all the factors of composite number \(4000\)?
- \(18\)
- \(24\)
- \(26\)
- \(16\)

Answer: (b) \(24\)

Solution: \(4000\)

\(= 2 \times 2 \times 2 \times 2 \times 2 \times 5 \times 5 \times 5\)

\(= 2^5 \times 5^3\)

\(factors \ of \ composite \ number\)

\(= (5 + 1) \ (3 + 1) = 6 \times 4 = 24\)

Solution: \(4000\)

\(= 2 \times 2 \times 2 \times 2 \times 2 \times 5 \times 5 \times 5\)

\(= 2^5 \times 5^3\)

\(factors \ of \ composite \ number\)

\(= (5 + 1) \ (3 + 1) = 6 \times 4 = 24\)

- Find the factors of composite number \(29\)?
- \(5\)
- \(3\)
- \(1\)
- \(2\)

Answer: (d) \(2\)

Solution: \(29\) is a prime number and any prime number have only two factors \(1\) and itself.

Solution: \(29\) is a prime number and any prime number have only two factors \(1\) and itself.

Lec 1: Introduction to Number System
Lec 2: Factors of Composite Number
Questions and Answers-1
Lec 3: Basic Remainder Theorem
Questions and Answers-2
Lec 4: Polynomial Remainder Theorem
Questions and Answers-3
Questions and Answers-4
Questions and Answers-5
Lec 5: LCM of Numbers
Questions and Answers-6
Lec 6: HCF of Numbers
Questions and Answers-7
Questions and Answers-8
Lec 7: Divisibility Rules of Numbers
Questions and Answers-9
Questions and Answers-10
Questions and Answers-11
Questions and Answers-12
Questions and Answers-13
Questions and Answers-14
Questions and Answers-15
Questions and Answers-16
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