# Time Speed and Distance Quantitative Aptitude Questions:

#### Overview:

 Questions and Answers Type: MCQ (Multiple Choice Questions). Main Topic: Quantitative Aptitude. Quantitative Aptitude Sub-topic: Time Speed and Distance Aptitude Questions and Answers. Number of Questions: 10 Questions with Solutions.

1. If a women covered $$120 \ km$$ in $$3 \ hours$$, then find the speed of the women?

1. $$25 \ km/hr$$
2. $$30 \ km/hr$$
3. $$35 \ km/hr$$
4. $$40 \ km/hr$$

Answer: (d) $$40 \ km/hr$$

Solution: Given, distance covered = $$120 \ km$$

time taken = $$3 \ hours$$

then the speed of the women, $$Speed = \frac{distance \ covered}{time \ taken}$$ $$= \frac{120}{3} = 40 \ km/hr$$

1. If a $$170 \ meter$$ long train crossed a $$70 \ meter$$ long platform with the speed of $$45 \ km/hr$$, then find the time taken by train to cross the platform?

1. $$15.6 \ seconds$$
2. $$18.4 \ seconds$$
3. $$12.6 \ seconds$$
4. $$11.8 \ seconds$$

Answer: (b) $$18.4 \ seconds$$

Solution: Given, length of the train $$(l_m) = 170 \ meter$$

length of the platform $$(l_s) = 60 \ meter$$

speed of the train $$(s_m) = 45 \ km/hr$$ $$= 45 \times \frac{5}{18} \ m/sec$$, then $$Time \ taken = \frac{l_m + l_s}{s_m}$$ $$= \frac{170 + 60}{45 \times \frac{5}{18}}$$ $$= \frac{230 \times 18}{45 \times 5}$$ $$= \frac{4140}{225} = 18.4 \ sec.$$

1. Two trains x and y, start moving at the same time from points A and B respectively towards each other. After passing each other, trains take $$16 \ hours$$ and $$4 \ hours$$ to reach points A and B respectively. If the train x is moving at the speed of $$80 \ km/hr$$, then find the speed of train y?

1. $$120 \ km/hr$$
2. $$135 \ km/hr$$
3. $$145 \ km/hr$$
4. $$160 \ km/hr$$

Answer: (d) $$160 \ km/hr$$

Solution: Given, speed of the train x $$(s_1) = 80 \ km/hr$$

time taken by the train x to reach the point B $$(T_1) = 16 \ hours$$

time taken by the train y to reach the point A $$(T_2) = 4 \ hours$$, then $$\frac{s_1}{s_2} = \sqrt{\frac{T_2}{T_1}}$$ $$\frac{80}{s_2} = \sqrt{\frac{4}{16}}$$ $$\frac{80}{s_2} = \sqrt{\frac{1}{4}}$$ $$\frac{80}{s_2} = \frac{1}{2}$$ $$s_2 = 160 \ km/hr$$

1. Two $$120 \ meter$$ and $$150 \ meter$$ long trains moving in the same direction at the speed of $$80 \ km/hr$$ and $$70 \ km/hr$$ respectively. Find the time taken by the faster train to cross the slower train?

1. $$95.5 \ seconds$$
2. $$97.2 \ seconds$$
3. $$96.6 \ seconds$$
4. $$92.3 \ seconds$$

Answer: (b) $$97.2 \ seconds$$

Solution: Given, length of the first train $$(l_1) = 120 \ meter$$

length of the second train $$(l_2) = 150 \ meter$$

speed of the first train $$(s_1) = 80 \ km/hr$$ $$= 80 \times \frac{5}{18} \ m/sec$$ speed of the second train $$(s_2) = 70 \ km/hr$$ $$= 70 \times \frac{5}{18} \ m/sec$$ then, $$time \ taken \ (T) = \frac{l_1 + l_2}{s_1 - s_2}$$ $$= \frac{120 + 150}{\frac{5}{18} \ (80 - 70)}$$ $$= \frac{270 \times 18}{50}$$ $$T = 97.2 \ seconds$$

1. If a man covered $$80 \ km$$ distance with the speed of $$40 \ km/hr$$, then find the time taken by the man to cover the distance?

1. $$1 \ hour$$
2. $$2 \ hours$$
3. $$3 \ hours$$
4. $$4 \ hours$$

Answer: (b) $$2 \ hours$$

Solution: Given, distance covered = $$80 \ km$$

speed = $$40 \ km/hr$$, then $$Speed = \frac{distance \ covered}{time \ taken}$$ $$40 = \frac{80}{T}$$ $$T = 2 \ hours$$

1. A $$300 \ meter$$ long train and a bicycle, moving in the same direction, the speed of the train and bicycle are $$50 \ km/hr$$ and $$20 \ km/hr$$ respectively. If length of the bicycle is not considered, then find the time taken by the train to cross the bicycle?

1. $$30 \ seconds$$
2. $$32 \ seconds$$
3. $$34 \ seconds$$
4. $$36 \ seconds$$

Answer: (d) $$36 \ seconds$$

Solution: Given, length of the first train $$(l_1) = 300 \ meter$$

speed of the train $$(s_1) = 50 \ km/hr$$ $$= 50 \times \frac{5}{18} \ m/sec$$ speed of the bicycle $$(s_2) = 20 \ km/hr$$ $$= 20 \times \frac{5}{18} \ m/sec$$ then, $$time \ taken \ (T) = \frac{l_1}{s_1 - s_2}$$ $$= \frac{300}{\frac{5}{18} \ (50 - 20)}$$ $$= \frac{300 \times 18}{150}$$ $$T = 36 \ seconds$$

1. A train is moving from point A to point B with the initial speed of $$30 \ km/hr$$ and after $$2 \ hours$$, speed of the train increases $$50 \ km/hr$$, then find the rate of the acceleration of the train?

1. $$10 \ km/hr$$
2. $$12 \ km/hr$$
3. $$13 \ km/hr$$
4. $$15 \ km/hr$$

Answer: (a) $$10 \ km/hr$$

Solution: Given, initial speed of the train $$(V_i) = 30 \ km/hr$$

final speed of the train $$(V_f) = 50 \ km/hr$$

time taken by the train to achieve the final speed $$(T) = 2 \ hours$$, then $$Acceleration \ (a) = \frac{V_f - V_i}{T}$$ $$= \frac{50 - 30}{2}$$ $$= \frac{20}{2} = 10 \ km/hr$$

1. A girl swims downstream with the speed of $$40 \ km/hr$$. If the speed of stream is $$10 \ km/hr$$, then find the speed of the girl in still water?

1. $$25 \ km/hr$$
2. $$28 \ km/hr$$
3. $$30 \ km/hr$$
4. $$32 \ km/hr$$

Answer: (c) $$30 \ km/hr$$

Solution: Given, speed of downstream $$(D_s) = 40 \ km/hr$$

speed of stream $$(S_s) = 10 \ km/hr$$

then speed of the girl in still water, $$B_s = D_s - S_s$$ $$B_s = 40 - 10$$ $$B_s = 30 \ km/hr$$

1. If a boat goes $$28 \ km$$ upstream and $$32 \ km$$ downstream, taking $$4 \ hours$$ each time, then find the speed of the boat in still water?

1. $$10.5 \ km/hr$$
2. $$8.5 \ km/hr$$
3. $$5.6 \ km/hr$$
4. $$7.5 \ km/hr$$

Answer: (d) $$7.5 \ km/hr$$

Solution: Given, speed of upstream $$(U_s) = \frac{28}{4} = 7 \ km/hr$$

speed of downstream $$(D_s) = \frac{32}{4} = 8 \ km/hr$$

then speed of the boat in still water, $$B_s = \frac{D_s + U_s}{2}$$ $$= \frac{8 + 7}{2}$$ $$= \frac{15}{2} = 7.5 \ km/hr$$

1. If a man swims $$14 \ km$$ downstream and $$8 \ km$$ upstream, taking $$2 \ hours$$ each time, then find the speed of stream?

1. $$1.0 \ km/hr$$
2. $$1.3 \ km/hr$$
3. $$1.4 \ km/hr$$
4. $$1.5 \ km/hr$$

Answer: (d) $$1.5 \ km/hr$$

Solution: Given, speed of downstream $$(D_s) = \frac{14}{2} = 7 \ km/hr$$

speed of upstream $$(U_s) = \frac{8}{2} = 4 \ km/hr$$

then speed of stream, $$S_s = \frac{D_s - U_s}{2}$$ $$= \frac{7 - 4}{2}$$ $$= \frac{3}{2} = 1.5 \ km/hr$$