# Time Speed and Distance Aptitude Solved Questions:

#### Overview:

 Questions and Answers Type: MCQ (Multiple Choice Questions). Main Topic: Quantitative Aptitude. Quantitative Aptitude Sub-topic: Time Speed and Distance Aptitude Questions and Answers. Number of Questions: 10 Questions with Solutions.

1. A train moves from the New Delhi railway station to Jaipur at the initial speed of $$45 \ km/hr$$ and after $$0.5 \ hr$$, speed of the train increases $$75 \ km/hr$$, then find the rate of acceleration of the train?

1. $$62 \ km/hr$$
2. $$60 \ km/hr$$
3. $$66 \ km/hr$$
4. $$68 \ km/hr$$

Answer: (b) $$60 \ km/hr$$

Solution: Given, Initial speed of the train $$(v_i) = 45 \ km/hr$$

final speed of the train $$(v_f) = 75 \ km/hr$$

time taken by the train to achieve the final speed $$(T) = 0.5 \ hours$$, then $$Acceleration \ (a) = \frac{v_f - v_i}{T}$$ $$= \frac{75 - 45}{0.5}$$ $$= \frac{30}{0.5} = 60 \ km/hr$$

1. The initial speed of a car is $$25 \ km/hr$$ and after $$2 \ hours$$ the speed of car increases $$65 \ km/hr$$, then find the rate of acceleration of car?

1. $$20 \ km/hr$$
2. $$22 \ km/hr$$
3. $$24 \ km/hr$$
4. $$25 \ km/hr$$

Answer: (a) $$20 \ km/hr$$

Solution: Given, initial speed of the car $$(v_i) = 25 \ km/hr$$

final speed of the car $$(v_f) = 65 \ km/hr$$

time taken by the car to achieve final speed $$(T) = 2 \ hours$$, then $$Acceleration \ (a) = \frac{v_f - v_i}{T}$$ $$= \frac{65 - 25}{2}$$ $$= \frac{40}{2} = 20 \ km/hr$$

1. A man travels from city A to city B with the initial speed of $$60 \ km/hr$$ and achieved the speed $$120 \ km/hr$$ with the acceleration rate $$30 \ km/hr$$, then find the time taken by the man to achieve the final speed?

1. $$1 \ hour$$
2. $$2 \ hours$$
3. $$3 \ hours$$
4. $$4 \ hours$$

Answer: (b) $$2 \ hours$$

Solution: Given, Initial speed of the man $$(v_i) = 60 \ km/hr$$

final speed of the man $$(v_f) = 120 \ km/hr$$

Acceleration $$(a) = 30 \ km/hr$$, then $$Acceleration \ (a) = \frac{v_f - v_i}{T}$$ $$30 = \frac{120 - 60}{T}$$ $$T = \frac{60}{30} = 2 \ hours$$

1. An express train travels $$800 \ km$$ in $$3 \ hours$$ and another $$700 \ km$$ in $$5 \ hours$$, then find the average speed of the train?

1. $$176.5 \ km/hr$$
2. $$185.5 \ km/hr$$
3. $$188.5 \ km/hr$$
4. $$187.5 \ km/hr$$

Answer: (d) $$187.5 \ km/hr$$

Solution: Given, total distance covered by the train = $$800 \ km + 700 \ km$$ = $$1500 \ km$$

total time taken by the train $$= 3 + 5 = 8 \ hours$$, then $$Average \ speed = \frac{distance \ covered}{time \ taken}$$ $$= \frac{1500}{8} = 187.5 \ km/hr$$

1. A man travels on bicycle with the initial speed of $$10 \ m/sec$$ and accelerated with the rate of $$2 \ m/sec$$, after $$60 \ seconds$$ the man achieved the final speed. Find the final speed of the man?

1. $$130 \ m/sec$$
2. $$125 \ m/sec$$
3. $$128 \ m/sec$$
4. $$132 \ m/sec$$

Answer: (a) $$130 \ m/sec$$

Solution: Given, initial speed of the man $$(v_i) = 10 \ m/sec$$

time taken by the man to achieve the final speed $$(T) = 60 \ seconds$$

acceleration rate of the bicycle $$(a) = 2 \ m/sec$$, then $$Acceleration \ (a) = \frac{v_f - v_i}{T}$$ $$2 = \frac{v_f - 10}{60}$$ $$120 = v_f - 10$$ $$v_f = 130 \ m/sec$$

1. A bus starts moving and after $$2 \ seconds$$ achieves the speed $$175 \ km/hr$$. If the bus acclerating with the rate of $$10 \ m/sec$$, then find the initial speed of the bus?

1. $$111.255 \ km/hr$$
2. $$115.936 \ km/hr$$
3. $$102.996 \ km/hr$$
4. $$108.672 \ km/hr$$

Answer: (c) $$102.996 \ km/hr$$

Solution: Given, final speed of the bus $$(v_f) = 175 \ km/hr$$ = $$175 \times \frac{5}{18}$$

time taken by the bus to achieve the final speed $$(T) = 2 \ seconds$$

rate of accleration of the bus $$(a) = 100 \ m/sec$$, then $$Acceleration \ (a) = \frac{v_f - v_i}{T}$$ $$10 = \frac{175 \times \frac{5}{18} - v_i}{2}$$ $$20 \times 18 = 175 \times 5 - 18 \ v_i$$ $$18 \ v_i = 515$$ $$v_i = 28.61 \ m/sec$$ $$v_i = 28.61 \times \frac{18}{5} \ km/hr$$ $$v_i = 102.996 \ km/hr$$

1. A man covered a certain distance in $$25 \ seconds$$ with the average speed of $$500 \ m/sec$$, then find distance covered by the man?

1. $$10.5 \ km$$
2. $$15.5 \ km$$
3. $$13.5 \ km$$
4. $$12.5 \ km$$

Answer: (d) $$12.5 \ km$$

Solution: Given, average speed of the man = $$500 \ m/sec$$

time taken by the man to cover the distance = $$25 \ seconds$$, then $$Average \ speed = \frac{distance \ covered}{time \ taken}$$ $$500 = \frac{distance \ covered}{25}$$ $$distance \ covered = 12,500 \ meter$$ $$= 12,500 \times \frac{1}{1000} = 12.5 \ km$$

1. Two cars are moving in the opposite direction towards each other with the speed of $$150 \ km/hr$$ and $$110 \ km/hr$$ respectively, then find the relative speed of the cars?

1. $$263 \ km/hr$$
2. $$260 \ km/hr$$
3. $$262 \ km/hr$$
4. $$258 \ km/hr$$

Answer: (b) $$260 \ km/hr$$

Solution: Given, speed of the first car $$(s_1) = 150 \ km/hr$$

speed of the second car $$(s_2) = 110 \ km/hr$$, then $$Relative \ speed = s_1 + s_2$$ $$= 150 + 110 = 260 \ km/hr$$

1. A man travels from station A to station B. He covered first $$200 \ km$$ with the speed of $$75 \ km/hr$$ and covered second $$200 \ km$$ with the speed of $$100 \ km/hr$$. Find the average speed of the man during the whole journey?

1. $$85.7 \ km/hr$$
2. $$86.5 \ km/hr$$
3. $$82.6 \ km/hr$$
4. $$87.6 \ km/hr$$

Answer: (a) $$85.7 \ km/hr$$

Solution: $$Average \ speed = \frac{distance \ covered}{time \ taken}$$ $$= \frac{d_1 + d_2}{\frac{d_1}{s_1} + \frac{d_2}{s_2}}$$ $$= \frac{200 + 200}{\frac{200}{75} + \frac{200}{100}}$$ $$= \frac{400 \times 300}{800 + 600}$$ $$= \frac{120000}{1400} = 85.7 \ km/hr$$

1. A girl covered a certain distance with the speed of $$10 \ m/sec$$. Find the speed of the girl in $$km/hr$$?

1. $$30 \ km/hr$$
2. $$36 \ km/hr$$
3. $$38 \ km/hr$$
4. $$32 \ km/hr$$

Answer: (b) $$36 \ km/hr$$

Solution: speed of the girl = $$10 \ m/sec$$, then $$= 10 \times \frac{18}{5} \ km/hr$$ $$= 36 \ km/hr$$