Questions and Answers Type: | MCQ (Multiple Choice Questions). |

Main Topic: | Quantitative Aptitude. |

Quantitative Aptitude Sub-topic: | Time Speed and Distance Aptitude Questions and Answers. |

Number of Questions: | 10 Questions with Solutions. |

- If a man covered \(70 \ km\) distance in \(2 \ hours\), then find out the speed of the man?
- \(32 \ km/hr\)
- \(36 \ km/hr\)
- \(38 \ km/hr\)
- \(35 \ km/hr\)

Answer: (d) \(35 \ km/hr\)

Solution: Given, distance covered by the man = \(70 \ km\), time taken = \(2 \ hours\), then the speed of the man, $$ speed = \frac{distance \ covered}{time \ taken} $$ $$ speed = \frac{70}{2} = 35 \ km/hr $$

Solution: Given, distance covered by the man = \(70 \ km\), time taken = \(2 \ hours\), then the speed of the man, $$ speed = \frac{distance \ covered}{time \ taken} $$ $$ speed = \frac{70}{2} = 35 \ km/hr $$

- If John covered \(120 / km\) distance at the speed of \(40 \ km/hr\) then find the time taken by the John to cover the distance?
- \(1 \ hours\)
- \(2 \ hours\)
- \(3 \ hours\)
- \(4 \ hours\)

Answer: (c) \(3 \ hours\)

Solution: Given, distance covered by the John = \(120 \ km\), speed = \(40 \ km/hr\), then $$ speed = \frac{distance \ covered}{time \ taken} $$ $$ 40 = \frac{120}{time \ taken} $$ $$ time \ taken = 3 \ hours $$

Solution: Given, distance covered by the John = \(120 \ km\), speed = \(40 \ km/hr\), then $$ speed = \frac{distance \ covered}{time \ taken} $$ $$ 40 = \frac{120}{time \ taken} $$ $$ time \ taken = 3 \ hours $$

- A man traveled from city A to city B at the speed of \(60 \ km/hr\) and reaches the city B in \(4 \ hours\), then find the distance covered by the man?
- \(200 \ km\)
- \(220 \ km\)
- \(240 \ km\)
- \(250 \ km\)

Answer: (c) \(240 \ km\)

Solution: Given, speed of the man = \(60 \ km/hr\), time taken = \(4 \ hours\), then $$ speed = \frac{distance \ covered}{time \ taken} $$ $$ 60 = \frac{distance \ covered}{4} $$ $$ distance \ covered = 240 \ km $$

Solution: Given, speed of the man = \(60 \ km/hr\), time taken = \(4 \ hours\), then $$ speed = \frac{distance \ covered}{time \ taken} $$ $$ 60 = \frac{distance \ covered}{4} $$ $$ distance \ covered = 240 \ km $$

- If a car moving at the speed of \(80 \ km/hr\), then find the speed of the car in \(m/sec\)?
- \(24.25 \ m/sec\)
- \(22.22 \ m/sec\)
- \(25.25 \ m/sec\)
- \(20.20 \ m/sec\)

Answer: (b) \(22.22 \ m/sec\)

Solution: speed of car = \(80 \ km/hr\), then $$ 80 \ km/hr = 80 \times \frac{5}{18} = 22.22 \ m/sec $$

Solution: speed of car = \(80 \ km/hr\), then $$ 80 \ km/hr = 80 \times \frac{5}{18} = 22.22 \ m/sec $$

- If speed of a bus is \(30 \ m/sec\), then find the speed of bus in \(km/hr\)?
- \(112 \ km/hr\)
- \(110 \ km/hr\)
- \(111 \ km/hr\)
- \(108 \ km/hr\)

Answer: (d) \(108 \ km/hr\)

Solution: speed of bus = \(30 \ m/sec\), then $$ 30 \ m/sec = 30 \times \frac{18}{5} = 108 \ km/hr $$

Solution: speed of bus = \(30 \ m/sec\), then $$ 30 \ m/sec = 30 \times \frac{18}{5} = 108 \ km/hr $$

- If two trains moving in the same direction with the speed of \(170 \ km/hr\) and \(90 \ km/hr\), respectively. Find the relative speed of the trains?
- \(80 \ km/hr\)
- \(86 \ km/hr\)
- \(82 \ km/hr\)
- \(88 \ km/hr\)

Answer: (a) \(80 \ km/hr\)

Solution: Given, speed of the first train \((s_1) = 170 \ km/hr\), speed of the second train \((s_2) = 90 \ km/hr\), then $$ Relative \ speed = s_1 - s_2 $$ $$ Relative \ speed = 170 - 90 $$ $$ Relative \ speed = 80 \ km/hr $$

Solution: Given, speed of the first train \((s_1) = 170 \ km/hr\), speed of the second train \((s_2) = 90 \ km/hr\), then $$ Relative \ speed = s_1 - s_2 $$ $$ Relative \ speed = 170 - 90 $$ $$ Relative \ speed = 80 \ km/hr $$

- Relative speed of two cars is \(75 \ km/hr\) moving in the same direction, if speed of second car is \(35 \ km/hr\), then find the speed of first car?
- \(108 \ km/hr\)
- \(114 \ km/hr\)
- \(112 \ km/hr\)
- \(110 \ km/hr\)

Answer: (d) \(110 \ km/hr\)

Solution: Given, relative speed = \(75 \ km/hr\), speed of second car \((s_2) = 35 \ km/hr\), then $$ relative \ speed = s_1 - s_2 $$ $$ 75 = s_1 - 35 $$ $$ s_1 = 110 \ km/hr $$

Solution: Given, relative speed = \(75 \ km/hr\), speed of second car \((s_2) = 35 \ km/hr\), then $$ relative \ speed = s_1 - s_2 $$ $$ 75 = s_1 - 35 $$ $$ s_1 = 110 \ km/hr $$

- If two buses are moving in opposite direction at the speed of \(45 \ km/hr\) and \(55 \ km/hr\) respectively, then find the relative speed of the buses?
- \(98 \ km/hr\)
- \(102 \ km/hr\)
- \(100 \ km/hr\)
- \(105 \ km/hr\)

Answer: (c) \(100 \ km/hr\)

Solution: Given, speed of first bus \((s_1) = 45 \ km/hr\), speed of second bus \((s_2) = 55 \ km/hr\), then relative speed of the buses, $$ Relative \ speed = s_1 + s_2 $$ $$ Relative \ speed = 45 + 55 $$ $$ Relative \ speed = 100 \ km/hr $$

Solution: Given, speed of first bus \((s_1) = 45 \ km/hr\), speed of second bus \((s_2) = 55 \ km/hr\), then relative speed of the buses, $$ Relative \ speed = s_1 + s_2 $$ $$ Relative \ speed = 45 + 55 $$ $$ Relative \ speed = 100 \ km/hr $$

- Relative speed of two trains is \(30 \ km/hr\) moving in the opposite direction. If speed of second train is \(25 \ km/hr\), then find the speed of first train?
- \(5 \ km/hr\)
- \(10 \ km/hr\)
- \(15 \ km/hr\)
- \(20 \ km/hr\)

Answer: (a) \(5 \ km/hr\)

Solution: Given, relative speed of the trains = \(30 \ km/hr\), speed of second train \((s_2) = 25 \ km/hr\), then $$ Relative \ speed = s_1 + s_2 $$ $$ 30 = s_1 + 25 $$ $$ s_1 = 5 \ km/hr $$

Solution: Given, relative speed of the trains = \(30 \ km/hr\), speed of second train \((s_2) = 25 \ km/hr\), then $$ Relative \ speed = s_1 + s_2 $$ $$ 30 = s_1 + 25 $$ $$ s_1 = 5 \ km/hr $$

- If there are two railway stations A and B. First train moving from station A to B at the speed of \(180 \ km/hr\) and second train moving from B to A. If relative speed of the trains is \(210 \ km/hr\), then find the speed of second train moving from B to A?
- \(25 \ km/hr\)
- \(30 \ km/hr\)
- \(32 \ km/hr\)
- \(35 \ km/hr\)

Answer: (b) \(30 \ km/hr\)

Solution: Given, speed of the first train \((s_1) = 180 \ km/hr\), relative speed of trains = \(210 \ km/hr\), then $$ Relative \ speed = s_1 + s_2 $$ $$ 210 = 180 + s_2 $$ $$ s_2 = 30 \ km/hr $$

Solution: Given, speed of the first train \((s_1) = 180 \ km/hr\), relative speed of trains = \(210 \ km/hr\), then $$ Relative \ speed = s_1 + s_2 $$ $$ 210 = 180 + s_2 $$ $$ s_2 = 30 \ km/hr $$

Lec 1: Introduction to Time, Speed and Distance
Exercise-1
Lec 2: Concept of Train and Platform Case (1)
Exercise-2
Lec 3: Concept of Train and Platform Case (2)
Exercise-3
Lec 4: Concept of Train and Platform Case (3)
Exercise-4
Lec 5: Concept of Train and Platform Case (4)
Exercise-5
Lec 6: Concept of Acceleration
Exercise-6
Lec 7: Concept of Boat and Stream Case (1) and Case (2)
Exercise-7
Lec 8: Concept of Boat and Stream Case (3)
Exercise-8
Exercise-9
Exercise-10