# Time and Work Aptitude Questions and Answers:

#### Overview:

 Questions and Answers Type: MCQ (Multiple Choice Questions). Main Topic: Quantitative Aptitude. Quantitative Aptitude Sub-topic: Time and Work Aptitude Questions and Answers. Number of Questions: 10 Questions with Solutions.

1. P is twice as efficient as Q, and finish the task $$5$$ days earlier than Q. Find number of days required to finish the task by P?

1. $$3 \ days$$
2. $$4 \ days$$
3. $$5 \ days$$
4. $$6 \ days$$

Answer: (c) $$5 \ days$$

Solution: Let P can complete the task in $$x$$ days and

Q can complete the task in $$2x$$ days, then $$2x - x = 5$$ $$x = 5$$ Hence, P can finish the task in $$5$$ days.

1. A is four times as efficient as B, and finish the task $$21$$ days earlier than B. Find number of days required to finish the task, if both are working simultaneously?

1. $$3.5 \ days$$
2. $$4.3 \ days$$
3. $$5.6 \ days$$
4. $$6.1 \ days$$

Answer: (c) $$5.6 \ days$$

Solution: Let A can complete the task in $$x$$ days and

B can complete the task in $$4x$$ days, then $$4x - x = 21$$ $$3x = 21$$ $$x = 7$$ $$4x = 28$$ together they can finish the part of the task $$= \frac{1}{7} + \frac{1}{28}$$ $$= \frac{5}{28}$$ Hence, they can finish the task in $$\frac{28}{5}$$ days or $$5.6$$ days.

1. M is five times as efficient as N, and finish the task $$16$$ days earlier than N. Find number of days required to finish the task by N?

1. $$10 \ days$$
2. $$12 \ days$$
3. $$15 \ days$$
4. $$20 \ days$$

Answer: (d) $$20 \ days$$

Solution: Let M can complete the task in $$x$$ days and

N can complete the task in $$5x$$ days, then $$5x - x = 16$$ $$4x = 16$$ $$x = 4$$ Hence, N can finish the task in $$5x$$ = $$20$$ days.

1. A is twice as efficient as B and together they can finish a task in $$12$$ days. Find number of days required to finish the same task by B?

1. $$23 \ days$$
2. $$28 \ days$$
3. $$36 \ days$$
4. $$38 \ days$$

Answer: (c) $$36 \ days$$

Solution: Let A can complete the task in $$x$$ days and

B can complete the task in $$2x$$ days, then $$\frac{1}{x} + \frac{1}{2x} = \frac{1}{12}$$ $$x = 18$$ $$2x = 36$$ Hence, B can finish the task in $$36$$ days.

1. P and Q together can finish a task in $$15$$ days and P alone can finish the same task in $$20$$ days. Find how many days are required for Q to finish the work alone?

1. $$30 \ days$$
2. $$40 \ days$$
3. $$50 \ days$$
4. $$60 \ days$$

Answer: (d) $$60 \ days$$

Solution: part of task Q can finish in one day $$= \frac{1}{15} - \frac{1}{20}$$ $$= \frac{1}{60}$$ Hence, Q alone can finish the task in $$60$$ days.

1. Vishal is three times as efficient as Rohan, and finish the task $$36$$ days earlier than Rohan. Find number of days required to finish the task, if both are working simultaneously?

1. $$13.5 \ days$$
2. $$14.3 \ days$$
3. $$15.6 \ days$$
4. $$16.1 \ days$$

Answer: (a) $$13.5 \ days$$

Solution: Let Vishal can complete the task in $$x$$ days and

Rohan can complete the task in $$3x$$ days, then $$3x - x = 36$$ $$2x = 36$$ $$x = 18$$ $$3x = 54$$ together they can finish the part of the task $$= \frac{1}{18} + \frac{1}{54}$$ $$= \frac{2}{27}$$ Hence, they can finish the task in $$\frac{27}{2}$$ days or $$13.5$$ days.

1. A can finish a work in $$7$$ days and B can finish the same work in $$10$$ days, then find how many days are required to finish the work, if both are working together?

1. $$3.3 \ days$$
2. $$4.1 \ days$$
3. $$5.5 \ days$$
4. $$6.6 \ days$$

Answer: (b) $$4.1 \ days$$

Solution: Given, $$x = 7 \ days$$, $$y = 10 \ days$$

If both A and B start working together then $$= \frac{xy}{x + y}$$ $$= \frac{7 \times 10}{7 + 10}$$ $$= \frac{70}{17}$$ $$= 4.1 \ days$$ Hence, together they can finish the work in $$4.1 \ days$$.

1. P, Q and R can complete a work in $$10$$, $$20$$ and $$25$$ days respectively. Find in how many days they can together finish the work together?

1. $$3.2 \ days$$
2. $$4.5 \ days$$
3. $$5.2 \ days$$
4. $$6.4 \ days$$

Answer: (c) $$5.2 \ days$$

Solution: All three together can finish the work in one day $$= \frac{1}{10} + \frac{1}{20} + \frac{1}{25}$$ $$= \frac{19}{100}$$ Hence, together they can finish the work in $$\frac{100}{19}$$ days or $$5.2$$ days.

1. A can complete a work in $$4$$ days and B can complete the same work in $$6$$ days, while C can completely destroy the work in $$12$$ days. If they start working at the same time, then in how many days will the work be completed?

1. $$3 \ days$$
2. $$4 \ days$$
3. $$5 \ days$$
4. $$6 \ days$$

Answer: (a) $$3 \ days$$

Solution: The part of work completed by A, B and C in one day $$= \frac{1}{4} + \frac{1}{6} - \frac{1}{12}$$ $$= \frac{1}{3}$$ Hence, the work will be completed in $$3$$ days.

1. P and Q can finish a work in $$10$$ days, Q and R can finish the same work in $$20$$ days and R & P can finish the same work in $$25$$ days. If they start working together, then in how many days they will finish the work?

1. $$10.5 \ days$$
2. $$15.4 \ days$$
3. $$17.5 \ days$$
4. $$18.3 \ days$$

Answer: (a) $$10.5 \ days$$

Solution: Given, $$x = 10$$, $$y = 20$$ and $$z = 25$$ then $$= \frac{2xyz}{xy + yz + zx}$$ $$= \frac{2 \times 10 \times 20 \times 25}{200 + 500 + 250}$$ $$= \frac{10000}{950}$$ $$= 10.5 \ days$$