# Time and Work Aptitude Questions and Answers

#### Overview:

 Questions and Answers Type: MCQ (Multiple Choice Questions). Main Topic: Quantitative Aptitude. Quantitative Aptitude Sub-topic: Time and Work Aptitude Questions and Answers. Number of Questions: 10 Questions with Solutions.

1. M can finish a work in five days and N can finish the same work in $$10$$ days, then find how many days are required to finish the work, if both are working together?

1. $$3.3 \ days$$
2. $$4.4 \ days$$
3. $$5.5 \ days$$
4. $$6.6 \ days$$

Answer: (a) $$3.3 \ days$$

Solution: Given, $$x = 5 \ days$$, $$y = 10 \ days$$

If both M and N start working together then $$= \frac{xy}{x + y}$$ $$= \frac{5 \times 10}{5 + 10}$$ $$= \frac{50}{15}$$ $$= 3.3 \ days$$ Hence, together they can finish the work in $$3.3 \ days$$.

1. Ram can finish a task in two days and Shyam can finish the same task in five days. If they start working together, then how many days are required to finish the task?

1. $$5.2 \ days$$
2. $$4.5 \ days$$
3. $$2.5 \ days$$
4. $$1.4 \ days$$

Answer: (d) $$1.4 \ days$$

Solution: Given, $$x = 2 \ days$$, $$y = 5 \ days$$

If both Ram and Shyam start working together then $$= \frac{xy}{x + y}$$ $$= \frac{2 \times 5}{2 + 5}$$ $$= \frac{10}{7}$$ $$= 1.4 \ days$$ Hence, together they can finish the task in $$1.4 \ days$$.

1. A man can finish $$50 \ \%$$ of a work in $$10$$ days. Find how many days will he take to complete the work five times?

1. $$100 \ days$$
2. $$110 \ days$$
3. $$120 \ days$$
4. $$150 \ days$$

Answer: (a) $$100 \ days$$

Solution: The man can finish $$\frac{1}{2}$$ part of the work in $$10$$ days

then one part of work he can finish $$= \frac{10}{1/2}$$ $$= 20 \ days$$ Hence, he will complete five times of work in days $$= 20 \times 5$$ $$= 100 \ days$$

1. John and Jack together can finish a task in $$5 \ days$$. If John alone can finish the same task in $$10 \ days$$, then how many days will Jack take to finish the same task alone?

1. $$25 \ days$$
2. $$15 \ days$$
3. $$10 \ days$$
4. $$5 \ days$$

Answer: (c) $$10 \ days$$

Solution: Both can finish the task in one day = $$\frac{1}{5}$$

John alone can finish the task in one day = $$\frac{1}{10}$$

then Jack alone can finish the task in one day $$= \frac{1}{5} - \frac{1}{10}$$ $$= \frac{1}{10}$$ Hence, Jack alone can finish the task in $$10$$ days.

1. Vishal is twice as efficient as Rohit. Together, they can finish a work in $$10 \ days$$. Find in how many days can Rohit alone finish the same task?

1. $$50 \ days$$
2. $$30 \ days$$
3. $$20 \ days$$
4. $$10 \ days$$

Answer: (b) $$30 \ days$$

Solution: Let Vishal can finish the task in $$x$$ days and

Rohit can finish the task in $$2x$$ days

Together, they can finish the task in days $$\frac{xy}{x + y} = 10$$ $$\frac{x \times 2x}{x + 2x} = 10$$ $$\frac{2x^2}{3x} = 10$$ $$\frac{2x}{3} = 10$$ $$x = 15$$ Hence, Rohit alone can finish the task in $$2x$$ days = $$30$$ days

1. If three friends A, B and C can complete a work in $$10$$, $$8$$ and $$2$$ days respectively. Find in how many days they can together finish the work together?

1. $$\frac{40}{29} \ days$$
2. $$\frac{29}{40} \ days$$
3. $$\frac{27}{38} \ days$$
4. $$\frac{38}{27} \ days$$

Answer: (a) $$\frac{40}{29} \ days$$

Solution: All three together can finish the work in one day $$= \frac{1}{10} + \frac{1}{8} + \frac{1}{2}$$ $$= \frac{29}{40}$$ Hence, together they can finish the work in $$\frac{40}{29}$$ days.

1. A man can finish a work in $$10$$ days, but with the help of his friend, he can finish the work in $$5$$ days. Find in how many days, his friend can finish the work, alone?

1. $$20 \ days$$
2. $$15 \ days$$
3. $$10 \ days$$
4. $$8 \ days$$

Answer: (c) $$10 \ days$$

Solution: together, they can finish the part of work in one day = $$\frac{1}{5}$$

the man alone can finish the part of work in one day = $$\frac{1}{10}$$

then, his friend alone can finish the part of work in one day $$= \frac{1}{5} - \frac{1}{10}$$ $$= \frac{1}{10}$$ Hence, his friend alone can finish the work in $$10$$ days.

1. A man can finish a work in two days and a women can finish the same work in four days. If they work together, then in how many days they can finish the work?

1. $$\frac{3}{4} \ days$$
2. $$\frac{4}{3} \ days$$
3. $$\frac{2}{3} \ days$$
4. $$\frac{3}{2} \ days$$

Answer: (b) $$\frac{4}{3} \ days$$

Solution: the man and women together can finish the part of work in one day $$= \frac{1}{2} + \frac{1}{4}$$ $$= \frac{3}{4}$$ Hence, together, they can finish the work in $$\frac{4}{3}$$ days.

1. Two friends M and N together can finish a task in $$20$$ days. If M alone can finish the task in $$5$$ days, then in how many days N alone can finish the same work?

1. $$6.6 \ days$$
2. $$5.6 \ days$$
3. $$4.5 \ days$$
4. $$3.2 \ days$$

Answer: (a) $$6.6 \ days$$

Solution: Given, $$x = 20$$, $$y = 5$$, then $$= \frac{xy}{x - y}$$ $$= \frac{20 \times 5}{20 - 5}$$ $$= \frac{100}{15}$$ $$= 6.6 \ days$$

1. A women and a girl can finish a work in $$12$$ days. If a women alone can finish the work in $$4$$ days, then in how many days the girl alone can finish the work?

1. $$5 \ days$$
2. $$6 \ days$$
3. $$7 \ days$$
4. $$8 \ days$$

Answer: (b) $$6 \ days$$

Solution: Given, $$x = 12$$, $$y = 4$$, then $$= \frac{xy}{x - y}$$ $$= \frac{12 \times 4}{12 - 4}$$ $$= \frac{48}{8}$$ $$= 6 \ days$$