# Time and Work Aptitude Questions and Answers:

#### Overview:

 Questions and Answers Type: MCQ (Multiple Choice Questions). Main Topic: Quantitative Aptitude. Quantitative Aptitude Sub-topic: Time and Work Aptitude Questions and Answers. Number of Questions: 10 Questions with Solutions.

1. P can complete a work in $$5$$ days and Q can complete the same work in $$10$$ days, while R can completely destroy the work in $$20$$ days. If they start working at the same time, then in how many days will the work be completed?

1. $$1 \ day$$
2. $$2 \ days$$
3. $$3 \ days$$
4. $$4 \ days$$

Answer: (d) $$4 \ days$$

Solution: The part of work completed by P, Q and R in one day $$= \frac{1}{5} + \frac{1}{10} - \frac{1}{20}$$ $$= \frac{1}{4}$$ Hence, the work will be completed in $$4$$ days

1. A child is trying to reach at the top of a tree which is $$53$$ meters of height. Child can climb upto $$5$$ meters in first hour but climb down to $$1$$ meter in next hour. Find the time required by the child to reach the top of the tree?

1. $$22 \ hours$$
2. $$25 \ hours$$
3. $$28 \ hours$$
4. $$30 \ hours$$

Answer: (b) $$25 \ hours$$

Solution: The child climbing up $$5$$ meters in first hour and climbing down $$1$$ meter in next hour, then

work done by the child will be $$4$$ meters in $$2$$ hours

so the child can be climbed $$48$$ meters in $$24$$ hours

Hence, the child climbed last five meters in one hour then, total time required by the child to climb the tree = $$24 + 1$$ = $$25$$ hours

1. A boy is trying to reach at the top of a plateform which is $$25$$ meters of height. boy can climb upto $$5$$ meters in first hour but climb down to $$3$$ meter in next hour. Find the time required by the boy to reach the top of the plateform?

1. $$21 \ hours$$
2. $$26 \ hours$$
3. $$27 \ hours$$
4. $$29 \ hours$$

Answer: (a) $$21 \ hours$$

Solution: The boy climbing up $$5$$ meters in first hour and climbing down $$3$$ meter in next hour, then

work done by the boy will be $$2$$ meters in $$2$$ hours

so the boy can be climbed $$20$$ meters in $$20$$ hours

Hence, he climbed last five meters in one hour then, total time required by the child to climb the tree = $$20 + 1$$ = $$21$$ hours

1. A pipe can fill the tank in $$6$$ hours and pipe B can empty the tank in $$12$$ hours. Find the time required to fill the tank, if both pipes are running simultaneously?

1. $$10 \ hours$$
2. $$12 \ hours$$
3. $$15 \ hours$$
4. $$16 \ hours$$

Answer: (b) $$12 \ hours$$

Solution: Part of the tank filled in one hour $$= \frac{1}{6} - \frac{1}{12}$$ $$= \frac{1}{12}$$ Hence, the tank will be filled in $$12$$ hours

1. Pipe P can fill the tank in $$8$$ hours and pipe Q can empty the tank in $$10$$ hours. Find the time required to fill the tank, if both pipes are running simultaneously?

1. $$20 \ hours$$
2. $$30 \ hours$$
3. $$40 \ hours$$
4. $$50 \ hours$$

Answer: (c) $$40 \ hours$$

Solution: Part of the tank filled in one hour $$= \frac{1}{8} - \frac{1}{10}$$ $$= \frac{1}{40}$$ Hence, the tank will be filled in $$40$$ hours

1. Vishal can build a wall in $$15$$ days and Rohan can build the same wall in $$20$$ days. If they start working together, then in how many days they will build the wall?

1. $$\frac{60}{7} \ days$$
2. $$\frac{7}{60} \ days$$
3. $$\frac{60}{9} \ days$$
4. $$\frac{9}{60} \ days$$

Answer: (a) $$\frac{60}{7} \ days$$

Solution: Both can build the part of wall in one day $$= \frac{1}{15} + \frac{1}{20}$$ $$= \frac{7}{60}$$ Hence, they can build the wall in $$\frac{60}{7}$$ days

1. A is twice as efficient as B, and finish the work $$10$$ days earlier than B. Find number of days required to finish the work by B?

1. $$20 \ days$$
2. $$26 \ days$$
3. $$25 \ days$$
4. $$28 \ days$$

Answer: (a) $$20 \ days$$

Solution: Let A requires $$x$$ days and B requires $$2x$$ days to finish the work, then $$2x - x = 10$$ $$x = 10 \ days$$ $$2x = 20 \ days$$ Hence, B requires $$20$$ days to finish the work.

1. A and B together can do a piece of work in $$20$$ days and A alone can do it in $$30$$ days. In how many days can B do it alone?

1. $$40 \ days$$
2. $$50 \ days$$
3. $$60 \ days$$
4. $$70 \ days$$

Answer: (c) $$60 \ days$$

Solution: both can do part of work in one day = $$\frac{1}{20}$$

A alone can do the part of work in one day = $$\frac{1}{30}$$

then B alone can do the part of work in one day $$= \frac{1}{20} - \frac{1}{30}$$ $$= \frac{1}{60}$$ Hence, b alone can complete the work in $$60$$ days.

1. $$3$$ men can do a work in $$4$$ days. How many men are needed to do the work in $$6$$ days?

1. $$2 \ men$$
2. $$3 \ men$$
3. $$4 \ men$$
4. $$5 \ men$$

Answer: (a) $$2 \ men$$

Solution: Given, $$3$$ men can do the work in $$4$$ days, so $$3 \times 4 = 12$$ then $$Man \times day = 12$$ $$M \times 6 = 12$$ $$M = 2$$ Hence, $$2$$ men are needed to do the work in $$6$$ days.

1. $$5$$ men can do a work in $$10$$ days. How many men are needed to do the work in $$20$$ days?

1. $$10 \ days$$
2. $$20 \ days$$
3. $$30 \ days$$
4. $$40 \ days$$

Answer: (b) $$20 \ days$$

Solution: Given, $$5$$ men can do the work in $$10$$ days, so $$5 \times 10 = 50$$ then $$Man \times day = 50$$ $$M \times 20 = 50$$ $$M = 2.5$$ Hence, $$2.5$$ men are needed to do the work in $$20$$ days.