Directions: Study the following bar diagram carefully and answer the questions given below it.
The total number of students from different schools appeared and qualified for a competitive exam.
Find the average number of students qualified in the examination from schools P and Q is what percentage of the average number of students appeared for the examination from the same schools?
83.34 %
85.23 %
88.20 %
89.15 %
Answer: (a) 83.34 %Solution: The average number of students qualified from schools P and Q. $$ = \frac{1}{2} \ (600 + 650) $$ $$ = \frac{1}{2} \ (1250) $$ $$ = 625 $$ The Average number of students appeared from schools P and Q. $$ = \frac{1}{2} \ (700 + 800) $$ $$ = \frac{1}{2} \ (1500) $$ $$ = 750 $$ Required percentage $$ = \left[\frac{625}{750} \times 100\right] \ \% $$ $$ = 83.34 \ \% $$
Find out the ratio of the number of students who appeared to the number of students qualified in the exam from school S?
Find the number of students qualified for the exam, from the school S is approximately what percent of the total number of students qualified for the exam from all the schools together?
20 %
26 %
29 %
32 %
Answer: (b) 26 %Solution: Number of students qualified for the exam from the school S = 850Number of students qualified for the exam from all the schools together = \(600 + 650 + 700 + 850 + 500\) = \(3300\)Required percentage $$ = \left[\frac{850}{3300} \times 100\right] \ \% $$ $$ = 25.76 \ \% $$ $$ \approx 26 \ \% $$
Find the difference between the average number of students who appeared and qualified from all the schools together in the exam?
210
200
180
175
Answer: (c) 180Solution: The average number of students appeared for the exam from all the schools together. = \(\frac{1}{5} \ (700 + 800 + 900 + 1000 + 800)\)= \(\frac{1}{5} \times 4200\)= 840The average number of students qualified for the exam from all the schools together. = \(\frac{1}{5} \ (600 + 650 + 700 + 850 + 500)\)= \(\frac{1}{5} \times 3300\)= 660Requaired difference = \(840 - 660\) = \(180s\)