Questions and Answers Type: | MCQ (Multiple Choice Questions). |

Main Topic: | Data Interpretation. |

Data Interpretation Sub-topic: | Bar Graph Questions and Answers. |

Number of Questions: | 5 Questions with Solutions. |

**Directions:** Study the following bar diagram carefully and answer the questions given below it.

**The total number of students from different schools appeared and qualified for a competitive exam.**

- Find the average number of students qualified in the examination from schools P and Q is what percentage of the average number of students appeared for the examination from the same schools?
- 83.34 %
- 85.23 %
- 88.20 %
- 89.15 %

Answer: (a) 83.34 %

Solution: The average number of students qualified from schools P and Q. $$ = \frac{1}{2} \ (600 + 650) $$ $$ = \frac{1}{2} \ (1250) $$ $$ = 625 $$ The Average number of students appeared from schools P and Q. $$ = \frac{1}{2} \ (700 + 800) $$ $$ = \frac{1}{2} \ (1500) $$ $$ = 750 $$ Required percentage $$ = \left[\frac{625}{750} \times 100\right] \ \% $$ $$ = 83.34 \ \% $$

Solution: The average number of students qualified from schools P and Q. $$ = \frac{1}{2} \ (600 + 650) $$ $$ = \frac{1}{2} \ (1250) $$ $$ = 625 $$ The Average number of students appeared from schools P and Q. $$ = \frac{1}{2} \ (700 + 800) $$ $$ = \frac{1}{2} \ (1500) $$ $$ = 750 $$ Required percentage $$ = \left[\frac{625}{750} \times 100\right] \ \% $$ $$ = 83.34 \ \% $$

- Find out the ratio of the number of students who appeared to the number of students qualified in the exam from school S?
- 15:11
- 13:9
- 20:17
- 22:19

Answer: (c) 20:17

Solution: Required ratio $$ = \frac{1000}{850} $$ $$ = \frac{20}{17} $$ $$ = 20:17 $$

Solution: Required ratio $$ = \frac{1000}{850} $$ $$ = \frac{20}{17} $$ $$ = 20:17 $$

- Find out the ratio of the number of students who appeared in the exam from school S to the number of students who appeared in the exam from school T?
- 2:3
- 4:3
- 5:4
- 6:5

Answer: (c) 5:4

Solution: Required ratio $$ = \frac{1000}{800} $$ $$ = \frac{10}{8} $$ $$ = \frac{5}{4} = 5:4 $$

Solution: Required ratio $$ = \frac{1000}{800} $$ $$ = \frac{10}{8} $$ $$ = \frac{5}{4} = 5:4 $$

- Find the number of students qualified for the exam, from the school S is approximately what percent of the total number of students qualified for the exam from all the schools together?
- 20 %
- 26 %
- 29 %
- 32 %

Answer: (b) 26 %

Solution: Number of students qualified for the exam from the school S = 850

Number of students qualified for the exam from all the schools together = \(600 + 650 + 700 + 850 + 500\) = \(3300\)

Required percentage $$ = \left[\frac{850}{3300} \times 100\right] \ \% $$ $$ = 25.76 \ \% $$ $$ \approx 26 \ \% $$

Solution: Number of students qualified for the exam from the school S = 850

Number of students qualified for the exam from all the schools together = \(600 + 650 + 700 + 850 + 500\) = \(3300\)

Required percentage $$ = \left[\frac{850}{3300} \times 100\right] \ \% $$ $$ = 25.76 \ \% $$ $$ \approx 26 \ \% $$

- Find the difference between the average number of students who appeared and qualified from all the schools together in the exam?
- 210
- 200
- 180
- 175

Answer: (c) 180

Solution: The average number of students appeared for the exam from all the schools together.

= \(\frac{1}{5} \ (700 + 800 + 900 + 1000 + 800)\)

= \(\frac{1}{5} \times 4200\)

= 840

The average number of students qualified for the exam from all the schools together.

= \(\frac{1}{5} \ (600 + 650 + 700 + 850 + 500)\)

= \(\frac{1}{5} \times 3300\)

= 660

Requaired difference = \(840 - 660\) = \(180s\)

Solution: The average number of students appeared for the exam from all the schools together.

= \(\frac{1}{5} \ (700 + 800 + 900 + 1000 + 800)\)

= \(\frac{1}{5} \times 4200\)

= 840

The average number of students qualified for the exam from all the schools together.

= \(\frac{1}{5} \ (600 + 650 + 700 + 850 + 500)\)

= \(\frac{1}{5} \times 3300\)

= 660

Requaired difference = \(840 - 660\) = \(180s\)