Questions and Answers Type: | MCQ (Multiple Choice Questions). |

Main Topic: | Quantitative Aptitude. |

Quantitative Aptitude Sub-topic: | Profit and Loss Aptitude Questions and Answers. |

Number of Questions: | 10 Questions with Solutions. |

- A seller sold an article for \(Rs.15000\) and gained \(10 \ \%\) profit. Find the cost price of the article?
- \(Rs.13636.36\)
- \(Rs.12358.52\)
- \(Rs.12246.68\)
- \(Rs.13530.24\)

Answer: (a) \(Rs.13636.36\)

Solution: Given, selling price (SP) = \(Rs.15000\)

profit percent = \(10 \ \%\), then $$ SP = \frac{100 + P \ \%}{100} \times CP $$ $$ 15000 = \frac{100 + 10}{100} \times CP $$ $$ CP = Rs.13636.36 $$

Solution: Given, selling price (SP) = \(Rs.15000\)

profit percent = \(10 \ \%\), then $$ SP = \frac{100 + P \ \%}{100} \times CP $$ $$ 15000 = \frac{100 + 10}{100} \times CP $$ $$ CP = Rs.13636.36 $$

- The market price of a mobile is \(Rs.8000\), which is \(10 \ \%\) greater than the cost price. If it is sold at a discount of \(2 \ \%\) on the market price, then find the profit percent of the seller?
- \(5.6 \ \%\)
- \(7.8 \ \%\)
- \(6.5 \ \%\)
- \(8.2 \ \%\)

Answer: (b) \(7.8 \ \%\)

Solution: Given, market price (selling price) = \(Rs.8000\)

market price is \(10 \ \%\) greater than the cost price then the actual cost price of the mobile $$ SP = \frac{100 + P \ \%}{100} \times CP $$ $$ 8000 = \frac{100 + 10}{100} \times CP $$ $$ CP = Rs.7272.72 $$ If mobile sold at \(2 \ \%\) discount then $$ SP = \frac{100 - L \ \%}{100} \times CP $$ $$ SP = \frac{98}{100} \times 8000 $$ $$ SP = Rs.7840 $$ profit on cost price, $$ Profit = 7840 - 7272.72 $$ $$ = Rs.567.28 $$ then the profit percent, $$ P \ \% = \frac{567.28}{7272.72} \times 100 $$ $$ = 7.8 \ \% $$

Solution: Given, market price (selling price) = \(Rs.8000\)

market price is \(10 \ \%\) greater than the cost price then the actual cost price of the mobile $$ SP = \frac{100 + P \ \%}{100} \times CP $$ $$ 8000 = \frac{100 + 10}{100} \times CP $$ $$ CP = Rs.7272.72 $$ If mobile sold at \(2 \ \%\) discount then $$ SP = \frac{100 - L \ \%}{100} \times CP $$ $$ SP = \frac{98}{100} \times 8000 $$ $$ SP = Rs.7840 $$ profit on cost price, $$ Profit = 7840 - 7272.72 $$ $$ = Rs.567.28 $$ then the profit percent, $$ P \ \% = \frac{567.28}{7272.72} \times 100 $$ $$ = 7.8 \ \% $$

- A man purchased a book at \(Rs.400\) and sold it at a profit of \(5 \ \%\). What would have been the increase in the profit percent if it was sold for \(Rs.450\)?
- \(7.5 \ \%\)
- \(5.5 \ \%\)
- \(8.5 \ \%\)
- \(4.5 \ \%\)

Answer: (a) \(7.5 \ \%\)

Solution: profit amount if book is sold at the profit of \(5 \ \%\), $$ = 400 \times \frac{5}{100} = Rs.20 $$ profit amount if book is sold at \(Rs.450\), $$ = 450 - 400 = Rs.50 $$ Hence, increased profit percent, $$ P \ \% = \frac{50 - 20}{400} \times 100 $$ $$ = 7.5 \ \% $$

Solution: profit amount if book is sold at the profit of \(5 \ \%\), $$ = 400 \times \frac{5}{100} = Rs.20 $$ profit amount if book is sold at \(Rs.450\), $$ = 450 - 400 = Rs.50 $$ Hence, increased profit percent, $$ P \ \% = \frac{50 - 20}{400} \times 100 $$ $$ = 7.5 \ \% $$

- A man purchased \(100\) chocolates at the rate of \(Rs.10\) per dozen. If the man sold all the chocolates at the rate of \(Rs.2\) per chocolate, then find the profit percent of the man?
- \(112.23 \ \%\)
- \(136.58 \ \%\)
- \(140.96 \ \%\)
- \(142.12 \ \%\)

Answer: (c) \(140.96 \ \%\)

Solution: cost price of \(12\) chocolates = \(Rs.10\)

cost price of \(1\) chocolate = \(\frac{10}{12}\) = \(Rs.0.83\)

selling price of \(1\) chocolate = \(Rs.2\)

profit amount per chocolates = \(2 - 0.83\) = \(Rs.1.17\)

then profir percent, $$ P \ \% = \frac{1.17}{0.83} \times 100 $$ $$ = 140.96 \ \% $$

Solution: cost price of \(12\) chocolates = \(Rs.10\)

cost price of \(1\) chocolate = \(\frac{10}{12}\) = \(Rs.0.83\)

selling price of \(1\) chocolate = \(Rs.2\)

profit amount per chocolates = \(2 - 0.83\) = \(Rs.1.17\)

then profir percent, $$ P \ \% = \frac{1.17}{0.83} \times 100 $$ $$ = 140.96 \ \% $$

- A girl bought a dress at \(Rs.5000\) and sold it at \(Rs.4500\). Find the loss percent of the girl?
- \(5 \ \%\)
- \(10 \ \%\)
- \(15 \ \%\)
- \(20 \ \%\)

Answer: (b) \(10 \ \%\)

Solution: Given, cost price (CP) = \(Rs.5000\)

selling price (SP) = \(Rs.4500\), then $$ SP = \frac{100 - L \ \%}{100} \times CP $$ $$ 4500 = \frac{100 - L \ \%}{100} \times 5000 $$ $$ L \ \% = 10 \ \% $$

Solution: Given, cost price (CP) = \(Rs.5000\)

selling price (SP) = \(Rs.4500\), then $$ SP = \frac{100 - L \ \%}{100} \times CP $$ $$ 4500 = \frac{100 - L \ \%}{100} \times 5000 $$ $$ L \ \% = 10 \ \% $$

- A man sold a book at \(Rs.1000\) and gained \(20 \ \%\) profit find the cost price of the book?
- \(Rs.800.63\)
- \(Rs.735.33\)
- \(Rs.833.33\)
- \(Rs.655.34\)

Answer: (c) \(Rs.833.33\)

Solution: Given, selling price (SP) = \(Rs.1000\)

profit percent = \(20 \ \%\), then $$ SP = \frac{100 + P \ \%}{100} \times CP $$ $$ 1000 = \frac{100 + 20}{100} \times CP $$ $$ CP = Rs.833.33 $$

Solution: Given, selling price (SP) = \(Rs.1000\)

profit percent = \(20 \ \%\), then $$ SP = \frac{100 + P \ \%}{100} \times CP $$ $$ 1000 = \frac{100 + 20}{100} \times CP $$ $$ CP = Rs.833.33 $$

- A shopkeeper purchased bananas at the rate of \(Rs.80\) per hundred. If he spends \(10 \ \%\) on the transportation, then what should be the selling price per hundred to earn a profit of \(20 \ \%\)?
- \(Rs.104.3\)
- \(Rs.106.2\)
- \(Rs.104.5\)
- \(Rs.105.6\)

Answer: (d) \(Rs.105.6\)

Solution: cost of hundred bananas after transportation, $$ = 80 + 80 \times \frac{10}{100} $$ $$ = Rs.88 $$ selling price per hundred bananas to earn \(20 \ \%\) profit, $$ = 88 + 88 \times \frac{20}{100} $$ $$ = Rs.105.6 $$

Solution: cost of hundred bananas after transportation, $$ = 80 + 80 \times \frac{10}{100} $$ $$ = Rs.88 $$ selling price per hundred bananas to earn \(20 \ \%\) profit, $$ = 88 + 88 \times \frac{20}{100} $$ $$ = Rs.105.6 $$

- A man purchased chocolates at the rate of \(Rs.50\) per hundred. He spends \(20 \ \%\) on the transportation. Find the cost price of the chocolates per hundred after transportation?
- \(Rs.80\)
- \(Rs.75\)
- \(Rs.60\)
- \(Rs.65\)

Answer: (c) \(Rs.60\)

Solution: cost of hundred chocolates after transportation, $$ = 50 + 50 \times \frac{20}{100} $$ $$ = Rs.60 $$

Solution: cost of hundred chocolates after transportation, $$ = 50 + 50 \times \frac{20}{100} $$ $$ = Rs.60 $$

- A man bought a watercooler for \(Rs.5000\) and spends \(10 \ \%\) on transportation. Find the cost price of the watercooler after transportation?
- \(Rs.5200\)
- \(Rs.5300\)
- \(Rs.5400\)
- \(Rs.5500\)

Answer: (d) \(5500\)

Solution: cost of watercooler after transportation, $$ = 5000 + 5000 \times \frac{10}{100} $$ $$ = Rs.5500 $$

Solution: cost of watercooler after transportation, $$ = 5000 + 5000 \times \frac{10}{100} $$ $$ = Rs.5500 $$

- When an article is sold for \(Rs.80\), there is a loss of \(20 \ \%\). Find the cost price of the article?
- \(Rs.110\)
- \(Rs.120\)
- \(Rs.100\)
- \(Rs.150\)

Answer: (c) \(Rs.100\)

Solution: Given, selling price (SP) = \(Rs.80\)

Loss percent = \(20 \ \%\), then $$ SP = \frac{100 - L \ \%}{100} \times CP $$ $$ 80 = \frac{100- 20}{100} \times CP $$ $$ CP = Rs.100 $$

Solution: Given, selling price (SP) = \(Rs.80\)

Loss percent = \(20 \ \%\), then $$ SP = \frac{100 - L \ \%}{100} \times CP $$ $$ 80 = \frac{100- 20}{100} \times CP $$ $$ CP = Rs.100 $$

Lec 1: Introduction
Exercise-1
Lec 2: Profit and Loss Case-1
Exercise-2
Lec 3: Profit and Loss Case-2
Exercise-3
Lec 4: Profit and Loss Case-3
Exercise-4
Lec 5: Case of Discount
Exercise-5