Successive Percentage Change Aptitude Formulas:

Overview:

 Topic Included: Formulas, Definitions & Exmaples. Main Topic: Quantitative Aptitude. Quantitative Aptitude Sub-topic: Percentage Aptitude Notes & Questions. Questions for practice: 10 Questions & Answers with Solutions.

Case (3):

If $$P$$ is $$n \ \%$$ more than that of $$Q$$, then $$Q$$ is less than that of $$P$$ by percent $$(\%)$$- $$\left[\frac{n}{100 + n} \times 100 \right] \%$$

Example (1): If the income of Mr.John is $$20 \ \%$$ more than that of Mr.Jack's income, then how much percent $$(\%)$$ income of Mr. Jack is less than that of Mr.John's income?

Solution: Given value is $$n = 20 \ \%$$, then Mr.Jack's income less than that of Mr.John's income in percent $$(\%)$$,$$\left[\frac{n}{100 + n} \times 100 \right] \%$$ $$= \left[\frac{20}{100 + 20} \times 100 \right] \%$$ $$= 16.67 \ \% \ (Answer)$$

Example (2): If the weight of Mohan is $$10 \ \%$$ more than that of Ram's weight, then how much percent $$(\%)$$ weight of Ram is less than that of Mohan's weight?

Solution: Given value is $$n = 10 \ \%$$, then Ram's weight less than that of Mohan's weight in percent $$(\%)$$,$$\left[\frac{n}{100 + n} \times 100 \right] \%$$ $$= \left[\frac{10}{100 + 10} \times 100 \right] \%$$ $$= 9.09 \ \% \ (Answer)$$

Case (4):

If $$P$$ is $$n \ \%$$ less than that of $$Q$$, then $$Q$$ is more than that of $$P$$ by percent $$(\%)$$- $$\left[\frac{n}{100 - n} \times 100 \right] \%$$

Example (1): If the income of Mr.John is $$20 \ \%$$ less than that of Mr.Jack's income, then how much percent $$(\%)$$ income of Mr. Jack is more than that of Mr.John's income?

Solution: Given value is $$n = 20 \ \%$$, then Mr.Jack's income more than that of Mr.John's income in percent $$(\%)$$,$$\left[\frac{n}{100 - n} \times 100 \right] \%$$ $$= \left[\frac{20}{100 - 20} \times 100 \right] \% = 25 \ \% \ (Answer)$$

Example (2): If the population of India is $$10 \ \%$$ less than that of China's population, then how much percent $$(\%)$$ population of china is more than that of India's population?

Solution: Given value is $$n = 10 \ \%$$, then China's population more than that of India's population in percent $$(\%)$$,$$\left[\frac{n}{100 - n} \times 100 \right] \%$$ $$= \left[\frac{10}{100 - 10} \times 100 \right] \%$$ $$= 11.11 \ \% \ (Answer)$$