Topic Included: | Formulas, Definitions & Exmaples. |

Main Topic: | Quantitative Aptitude. |

Quantitative Aptitude Sub-topic: | Percentage Aptitude Notes & Questions. |

Questions for practice: | 10 Questions & Answers with Solutions. |

If \(P\) is \(n \ \%\) more than that of \(Q\), then \(Q\) is less than that of \(P\) by percent \((\%)\)- $$ \left[\frac{n}{100 + n} \times 100 \right] \%$$

**Example (1):** If the income of Mr.John is \(20 \ \%\) more than that of Mr.Jack's income, then how much percent \((\%)\) income of Mr. Jack is less than that of Mr.John's income?

**Solution:** Given value is \(n = 20 \ \%\), then Mr.Jack's income less than that of Mr.John's income in percent \((\%)\),$$ \left[\frac{n}{100 + n} \times 100 \right] \%$$ $$ = \left[\frac{20}{100 + 20} \times 100 \right] \%$$ $$ = 16.67 \ \% \ (Answer)$$

**Example (2):** If the weight of Mohan is \(10 \ \%\) more than that of Ram's weight, then how much percent \((\%)\) weight of Ram is less than that of Mohan's weight?

**Solution:** Given value is \(n = 10 \ \%\), then Ram's weight less than that of Mohan's weight in percent \((\%)\),$$ \left[\frac{n}{100 + n} \times 100 \right] \%$$ $$ = \left[\frac{10}{100 + 10} \times 100 \right] \%$$ $$ = 9.09 \ \% \ (Answer)$$

If \(P\) is \(n \ \%\) less than that of \(Q\), then \(Q\) is more than that of \(P\) by percent \((\%)\)- $$ \left[\frac{n}{100 - n} \times 100 \right] \%$$

**Example (1):** If the income of Mr.John is \(20 \ \%\) less than that of Mr.Jack's income, then how much percent \((\%)\) income of Mr. Jack is more than that of Mr.John's income?

**Solution:** Given value is \(n = 20 \ \%\), then Mr.Jack's income more than that of Mr.John's income in percent \((\%)\),$$ \left[\frac{n}{100 - n} \times 100 \right] \%$$ $$ = \left[\frac{20}{100 - 20} \times 100 \right] \% = 25 \ \% \ (Answer)$$

**Example (2):** If the population of India is \(10 \ \%\) less than that of China's population, then how much percent \((\%)\) population of china is more than that of India's population?

**Solution:** Given value is \(n = 10 \ \%\), then China's population more than that of India's population in percent \((\%)\),$$ \left[\frac{n}{100 - n} \times 100 \right] \%$$ $$ = \left[\frac{10}{100 - 10} \times 100 \right] \%$$ $$ = 11.11 \ \% \ (Answer)$$

Lec 1: Introduction to Percentage
Exercise-1
Lec 2: Percentage Case-1
Exercise-2
Lec 2: Percentage Case-2
Exercise-3
Lec 2: Percentage Case-3 & 4
Exercise-4
Exercise-5
Exercise-6
Exercise-7
Exercise-8
Exercise-9
Exercise-10