# Percentage Aptitude Questions and Answers:

#### Overview:

 Questions and Answers Type: MCQ (Multiple Choice Questions). Main Topic: Quantitative Aptitude. Quantitative Aptitude Sub-topic: Percentage Aptitude Questions and Answers. Number of Questions: 10 Questions with Solutions.

1. The present population of a village is 4550. If the male and female population increases by 10% and 15% successively and the population will become 5650 then find the present population of males in that village?

1. 5229
2. 5231
3. 5246
4. 5253

Solution: Let the number of male present population in that village is x.

Then the number of female present population in the village = $$(4550 - x)$$

$$110 \ \% \ of \ x + 15 \ \% \ of \ (4550 - x)$$ = $$5650$$

$$\frac{110x}{100} + \frac{15}{100} \times (4550 - x)$$ = $$5650$$

$$110x + 15 \times (4550 - x)$$ = $$5650 \times 100$$

$$110x + 68250 - 15x = 565,000$$

$$95x = 496,750$$

$$x = 5228.9$$

$$\approx 5229$$

Hence the male present population in the village is 5229.

1. A woman spent $2500 on festive shopping,$2000 on buying a refrigerator, and the remaining 40% of the total amount saved for other expenditures. What was the total amount she had?

1. $7200 2.$7500
3. $7600 4.$7700

Answer: (b) $7500 Solution: Let the total amount was$x then.$$(100 - 40) \ \% \ of \ x = 2500 + 2000$$ $$60 \ \% \ of \ x = 4500$$ $$\frac{60x}{100} = 4500$$ $$x = \frac{4500 \times 100}{60}$$ $$x = 7500$$ Hence the total amount was $7500. 1. The monthly income of a person was$25,000 and his monthly expenditure was \$18,000. If his income increased by 20% and his expenditure increased by 15% after one year then find the percentage increase in his savings after one year?

1. 28.21 %
2. 29.33 %
3. 30.56 %
4. 32.85 %

Solution: The amount saved by the person in the first year = $$(25000 - 18000)$$ = $$\ \ 7000$$

Increased income after one year = $$120 \ \% \ of \ 25000$$

= $$\left[\frac{120}{100} \times 25000\right]$$

= $$30,000$$

Increased expenditure after one year = $$115 \ \% \ of \ 18000$$

= $$\left[\frac{115}{100} \times 18000\right]$$

= $$\ \ 20,700$$

Saved amount after one year = $$(30,000 - 20,700)$$ = $$\ \ 9300$$

Increased saving amount after one year = $$(9300 - 7000)$$ = $$\ \ 2300$$

Increased savings after one year in percentage = $$\left[\frac{2300}{7000} \times 100\right]$$ = $$32.85 \ \%$$

1. Ram got 25% of the maximum marks in an exam and failed by 15 marks. Krishna who got 35% in the same exam, got 10 marks more than passing marks. What were the passing marks?

1. 74.5 Marks
2. 77.5 Marks
3. 79.5 Marks
4. 80.5 Marks

Solution: Let the maximum marks was $$x$$ then.$$(25 \ \% \ of \ x) + 15 = (35 \ \% \ of \ x) - 10$$ $$\frac{25x}{100} + 15 = \frac{35x}{100} - 10$$ $$15 + 10 = \frac{35x}{100} - \frac{25x}{100}$$ $$25 = \frac{10x}{100}$$ $$x = 250$$ Hence the minimum passing marks. $$= (25 \ \% \ of \ 250) + 15$$ $$= \frac{25}{100} \times 250 + 15$$ $$= 77.5 \ Marks$$

1. In the U.S. Presidential election between two candidates, 80% of voters cast their votes, out of which 5% of the votes were declared invalid. A candidate got 12,550 votes which were 70% of the total valid votes. Find the total number of votes enrolled for the election?

1. 23,410
2. 23,430
3. 23,590
4. 23,660

Solution: Let the total number of votes enrolled for the election was $$x$$, then

Number of votes cast = $$80 \ \% \ x$$ = $$\frac{80x}{100}$$

Valid electoral votes = $$95 \ \% \ of \ \frac{80x}{100}$$

A candidate got 70% of the total valid votes.

$$70 \ \% \ of \ \left[95 \ \% \ of \ \frac{80x}{100}\right]$$ = 12550

$$\frac{70}{100} \times \frac{95}{100} \times \frac{80x}{100}$$ = 12550

$$\frac{70 \times 95 \times 80x}{100 \times 100 \times 100}$$ = 12550

$$x = 23590.23$$

$$\approx 23590$$

Hence 23,590 votes enrolled for the election.