Percentage Aptitude Questions and Answers:


Overview:


Questions and Answers Type:MCQ (Multiple Choice Questions).
Main Topic:Quantitative Aptitude.
Quantitative Aptitude Sub-topic:Percentage Aptitude Questions and Answers.
Number of Questions:10 Questions with Solutions.

  1. The present population of a village is 4550. If the male and female population increases by 10% and 15% successively and the population will become 5650 then find the present population of males in that village?

    1. 5229
    2. 5231
    3. 5246
    4. 5253


Answer: (a) 5229

Solution: Let the number of male present population in that village is x.

Then the number of female present population in the village = \((4550 - x)\)

\(110 \ \% \ of \ x + 15 \ \% \ of \ (4550 - x)\) = \(5650\)

\(\frac{110x}{100} + \frac{15}{100} \times (4550 - x)\) = \(5650\)

\(110x + 15 \times (4550 - x)\) = \(5650 \times 100\)

\(110x + 68250 - 15x = 565,000\)

\(95x = 496,750\)

\(x = 5228.9\)

\(\approx 5229\)

Hence the male present population in the village is 5229.

  1. A woman spent $2500 on festive shopping, $2000 on buying a refrigerator, and the remaining 40% of the total amount saved for other expenditures. What was the total amount she had?

    1. $7200
    2. $7500
    3. $7600
    4. $7700


Answer: (b) $7500

Solution: Let the total amount was $x then.$$ (100 - 40) \ \% \ of \ x = 2500 + 2000 $$ $$ 60 \ \% \ of \ x = 4500 $$ $$ \frac{60x}{100} = 4500 $$ $$ x = \frac{4500 \times 100}{60} $$ $$ x = 7500 $$ Hence the total amount was $7500.

  1. The monthly income of a person was $25,000 and his monthly expenditure was $18,000. If his income increased by 20% and his expenditure increased by 15% after one year then find the percentage increase in his savings after one year?

    1. 28.21 %
    2. 29.33 %
    3. 30.56 %
    4. 32.85 %


Answer: (d) 32.85 %

Solution: The amount saved by the person in the first year = \((25000 - 18000)\) = \(\$ \ 7000\)

Increased income after one year = \(120 \ \% \ of \ 25000\)

= \(\left[\frac{120}{100} \times 25000\right]\)

= \(30,000\)

Increased expenditure after one year = \(115 \ \% \ of \ 18000\)

= \(\left[\frac{115}{100} \times 18000\right]\)

= \(\$ \ 20,700\)

Saved amount after one year = \((30,000 - 20,700)\) = \(\$ \ 9300\)

Increased saving amount after one year = \((9300 - 7000)\) = \(\$ \ 2300\)

Increased savings after one year in percentage = \(\left[\frac{2300}{7000} \times 100\right]\) = \(32.85 \ \%\)

  1. Ram got 25% of the maximum marks in an exam and failed by 15 marks. Krishna who got 35% in the same exam, got 10 marks more than passing marks. What were the passing marks?

    1. 74.5 Marks
    2. 77.5 Marks
    3. 79.5 Marks
    4. 80.5 Marks


Answer: (b) 77.5 Marks

Solution: Let the maximum marks was \(x\) then.$$ (25 \ \% \ of \ x) + 15 = (35 \ \% \ of \ x) - 10 $$ $$ \frac{25x}{100} + 15 = \frac{35x}{100} - 10 $$ $$ 15 + 10 = \frac{35x}{100} - \frac{25x}{100} $$ $$ 25 = \frac{10x}{100} $$ $$ x = 250 $$ Hence the minimum passing marks. $$ = (25 \ \% \ of \ 250) + 15 $$ $$ = \frac{25}{100} \times 250 + 15 $$ $$ = 77.5 \ Marks $$

  1. In the U.S. Presidential election between two candidates, 80% of voters cast their votes, out of which 5% of the votes were declared invalid. A candidate got 12,550 votes which were 70% of the total valid votes. Find the total number of votes enrolled for the election?

    1. 23,410
    2. 23,430
    3. 23,590
    4. 23,660


Answer: (c) 23,590

Solution: Let the total number of votes enrolled for the election was \(x\), then

Number of votes cast = \(80 \ \% \ x\) = \(\frac{80x}{100}\)

Valid electoral votes = \(95 \ \% \ of \ \frac{80x}{100}\)

A candidate got 70% of the total valid votes.

\(70 \ \% \ of \ \left[95 \ \% \ of \ \frac{80x}{100}\right]\) = 12550

\(\frac{70}{100} \times \frac{95}{100} \times \frac{80x}{100}\) = 12550

\(\frac{70 \times 95 \times 80x}{100 \times 100 \times 100}\) = 12550

\(x = 23590.23\)

\(\approx 23590\)

Hence 23,590 votes enrolled for the election.