# Average Aptitude Solved Questions:

#### Overview:

 Questions and Answers Type: MCQ (Multiple Choice Questions). Main Topic: Quantitative Aptitude. Quantitative Aptitude Sub-topic: Average Aptitude Questions and Answers. Number of Questions: 10 Questions with Solutions.

1. If the distance between two stations $$A$$ and $$B$$ is $$200 \ km$$. A train covers the distance from $$A$$ to $$B$$ At the average speed of $$100 \ km/hr$$ and returns from $$B$$ to $$A$$ at the average speed of $$x \ km/hr$$. The average speed of the train during the whole journey is $$70 \ km/hr$$, find the value of $$x \ ?$$

1. $$53 \ km/hr$$
2. $$52.84 \ km/hr$$
3. $$53.84 \ km/hr$$
4. $$55.23 \ km/hr$$

Answer: (c) $$53.84 \ km/hr$$

Solution: Given values, $$x_1 = 100 \ km/hr$$, $$x_2 = x \ km/hr$$, and the average speed $$= 70 \ km/hr$$, then $$Average \ speed = \frac{2 \ x_1 \ x_2}{x_1 + x_2}$$ $$70 = \frac{2 \times 100 \times x}{100 + x}$$ $$7000 + 70 \ x = 200 \ x$$ $$130 \ x = 7000$$ $$x = \frac{7000}{130} = 53.84 \ km/hr$$

1. A man travels first $$60 \ km$$ in $$1 / hr$$ and second $$50 \ km$$ in $$x \ hr$$. If the average speed of the man is $$40 \ km/hr$$ then find the value of $$x \ ?$$

1. $$1.05 \ hr$$
2. $$1.25 \ hr$$
3. $$1.50 \ hr$$
4. $$1.75 \ hr$$

Answer: (d) $$1.75 \ hr$$

Solution: Given values, $$d_1 = 60 \ km$$, $$d_2 = 50 \ km$$, $$t_1 = 1 \ hr$$, $$t_2 = x \ hr$$ and average speed $$= 40 \ km/hr$$ then, $$Average \ speed = \frac{d_1 + d_2}{t_1 + t_2}$$ $$40 = \frac{60 + 50}{1 + x}$$ $$40 + 40 \ x = 110$$ $$x = \frac{70}{40} = 1.75 \ hr$$

1. Find the average of numbers between $$10$$ to $$30$$ divisible by $$3 \ ?$$

1. $$18.5$$
2. $$19.5$$
3. $$20.5$$
4. $$16.5$$

Answer: (b) $$19.5$$.

Solution: First number divisible by $$3$$ after $$10$$ is $$12$$.

last number divisible by $$3$$ before $$30$$ is $$27$$. Then $$Average = \frac{12 + 27}{2}$$ $$= \frac{39}{2} = 19.5$$

1. The average of five numbers is $$70$$, if one number is excluded then Average becomes $$80$$. Find the excluded number?

1. $$30$$
2. $$32$$
3. $$35$$
4. $$36$$

Answer: (a) $$30$$

Solution: Average increases = $$80 - 70 = 10$$

Total increased number = $$10 \times 4 = 40$$

It means is $$40$$ less the average, then excluded number = $$70 - 40 = 30$$

1. A bus covers $$100 \ km$$ distance, first $$30 \ km$$ at the speed of $$50 \ km/hr$$, second $$30 \ km$$ at the speed of $$60 \ km/hr$$ and last $$40 \ km$$ at the speed of $$x \ km/hr$$. If the average speed of the bus during the whole journey is $$65 \ km/hr$$, then find the value of $$x \ ?$$

1. $$86$$
2. $$85$$
3. $$87$$
4. $$88$$

Answer: (b) $$85$$

Solution: $$Average \ speed = \frac{k_1 + k_2 + k_3}{3}$$ $$65 = \frac{50 + 60 + x}{3}$$ $$195 = 110 + x$$ $$x = 85 \ km/hr$$

1. Find the average of first four even natural numbers after multiplying by $$5$$ and divide by by $$2 \ ?$$

1. $$13.5$$
2. $$14.5$$
3. $$12.5$$
4. $$10.5$$

Answer: (c) $$12.5$$

Solution: First four even natural numbers = $$2, 4, 6, 8$$

First four even natural numbers after multiplying by $$5$$ and divide by $$2$$ = $$5, 10, 15, 20$$ then, $$Average = \frac{5 + 10 + 15 + 20}{4}$$ $$= \frac{50}{4} = 12.5$$

1. If the average of $$8$$ numbers is $$30$$ then find the average after multiplying the numbers by $$5 \ ?$$

1. $$150$$
2. $$160$$
3. $$158$$
4. $$156$$

Answer: (a) $$150$$

Solution: Average of $$8$$ numbers is $$30$$.

total value of $$8$$ numbers = $$8 \times 30 = 240$$

total value of $$8$$ numbers after multiplying the numbers by $$5$$ = $$240 \times 5 = 1200$$ then, $$Average = \frac{1200}{8} = 150$$

1. If the average weight of four men is $$65 \ kg$$ and the ratio of their weight is $$2 : 4 : 3 : 5$$, then find the weight of lowest weight man?

1. $$35.50 \ kg$$
2. $$37.25 \ kg$$
3. $$37.14 \ kg$$
4. $$41.26 \ kg$$

Answer: (c) $$37.14 \ kg$$

Solution: Let the weight of men = $$2x, 4x, 3x, 5x$$ then, $$65 = \frac{2x + 4x + 3x + 5x}{4}$$ $$14x = 260$$ $$x = 18.57$$ the weight of lowest weight man = $$2 \times 18.57 = 37.14 \ kg$$

1. Find the average of first three natural numbers of multiplying by $$10$$ and divide by $$5 \ ?$$

1. $$2$$
2. $$4$$
3. $$6$$
4. $$8$$

Answer: (b) $$4$$

Solution: First three natural numbers = $$1, 2, 3$$

First three natural numbers after multiplying by $$10$$ and divide by $$5$$ = $$2 , 4, 6$$ then, $$Average = \frac{2 + 4 + 6}{3} = \frac{12}{3} = 4$$

1. If a man travels three consecutive distances $$100 \ km$$, $$150 \ km$$, and $$200 \ km$$, at the speed of $$45 \ km/hr$$, $$55 \ km/hr$$, and $$x \ km/hr$$. If the average speed of the man during the whole journey is $$60 \ km/hr$$, then find the value of $$x \ ?$$

1. $$75 \ km/hr$$
2. $$88 \ km/hr$$
3. $$82 \ km/hr$$
4. $$80 \ km/hr$$

Answer: (d) $$80 \ km/hr$$

Solution: $$Average \ speed = \frac{k_1 + k_2 + k_3}{3}$$ $$60 = \frac{45 + 55 + x}{3}$$ $$x = 80 \ km/hr$$