# Average Aptitude Questions with Answers:

#### Overview:

 Questions and Answers Type: MCQ (Multiple Choice Questions). Main Topic: Quantitative Aptitude. Quantitative Aptitude Sub-topic: Average Aptitude Questions and Answers. Number of Questions: 10 Questions with Solutions.

1. Find out the average of six consecutive odd numbers starting from seven?

1. $$10$$
2. $$14$$
3. $$12$$
4. $$15$$

Answer: (c) $$12$$

Solution: Six odd numbers starting from seven are $$= 7, 9, 11, 13, 15$$. Then $$Average = \frac{7 + 9 + 11 + 13 + 15}{5}$$ $$= \frac{72}{6} = 12$$

1. Find out the average of five consecutive even numbers starting from $$10 \ ?$$

1. $$12$$
2. $$13$$
3. $$14$$
4. $$16$$

Answer: (c) $$14$$

Solution: Five even numbers starting from $$10$$ are $$10, 12, 14, 16, 18$$, then $$Average = \frac{10 + 12 + 14 + 16 + 18}{5}$$ $$= \frac{70}{5} = 14$$

1. If the average of $$5$$ numbers is $$3$$ then find the average after multiplying the number by $$6 \ ?$$

1. $$16$$
2. $$20$$
3. $$14$$
4. $$18$$

Answer: (d) $$18$$.

Solution: Given average of $$5$$ numbers = $$3$$

Total value of $$5$$ numbers = $$5 \times 3 = 15$$

Total value of five numbers after multiplying the numbers by $$6$$ = $$15 \times 6 = 90$$

then the new average $$= \frac{90}{5} = 18$$

1. If the average of $$7$$ numbers is $$5$$ then find the average after multiplying the numbers by $$9 \ ?$$

1. $$35$$
2. $$40$$
3. $$45$$
4. $$42$$

Answer: (c) $$45$$

Solution: Given average of $$7$$ numbers = $$5$$

Total value of $$7$$ numbers = $$7 \times 5 = 35$$

Total value of $$7$$ numbers after multiplying the numbers by $$9$$ = $$35 \times 9 = 315$$

then the new average $$= \frac{315}{7} = 45$$

1. If a train running between two stations and train covers first $$50 \ km$$ at the average speed of $$20 \ km/hr$$, second $$50 \ km$$ at the average speed of $$40 \ km/hr$$, and last $$50 \ km$$ at the average speed of $$50 \ km/hr$$. Find the average speed of the train during whole journey?

1. $$30.05 \ km/hr$$
2. $$31.56 \ km/hr$$
3. $$32.56 \ km/hr$$
4. $$33.26 \ km/hr$$

Answer: (b) $$31.56 \ km/hr$$

Solution: $$Average \ Speed = \frac{Total \ distance \ covered}{Total \ time \ taken}$$ $$Average \ Speed = \frac{50 + 50 + 50}{\frac{50}{20} + \frac{50}{40} + \frac{50}{50}}$$ $$= \frac{150 \times 4}{19} = \frac{600}{19} = 31.56 \ km/hr$$

1. If a man travels first $$100 \ km$$ at the average speed of $$60 \ km/hr$$, second $$150 \ km$$ at the average speed of $$80 \ km/hr$$, and last $$200 \ km$$ at the average speed of $$100 \ km/hr$$. Find the average speed of the man during the whole journey?

1. $$81.203$$
2. $$80.305$$
3. $$82.205$$
4. $$83.203$$

Answer: (a) $$81.203$$

Solution: $$Average \ Speed = \frac{Total \ distance \ traveled}{Total \ time \ taken}$$ $$Average \ Speed = \frac{100 + 150 + 200}{\frac{100}{60} + \frac{150}{80} + \frac{200}{100}}$$ $$= \frac{450 \times 24}{133} = \frac{10800}{133} = 81.203 \ km/hr$$

1. If the average age of three men is $$50$$ years and the ratio of their ages are $$5 : 7 : 8$$ then find the age of oldest man?

1. $$50 \ years$$
2. $$65 \ years$$
3. $$60 \ years$$
4. $$65 \ years$$

Answer: (c) $$60 \ years$$

Solution: Let the ages of men are $$5x, 7x,$$ and $$8x$$ years. then $$50 = \frac{5x + 7x + 8x}{3}$$ $$20x = 150$$ $$x = 7.5$$ Then the age of oldest man $$= 8 \times 7.5 = 60 \ years$$

1. If the average weight of five students is $$40 \ kg$$ and their weight ratio are $$2 : 4 : 5 : 6 : 8$$ then find the students who have the lowest and highest weight?

1. $$16 \ and \ 62 \ kg$$
2. $$16 \ and \ 64 \ kg$$
3. $$18 \ and \ 66 \ kg$$
4. $$15 \ and \ 68 \ kg$$

Answer: (b) $$16 \ and \ 64 \ kg$$

Solution: Let the weight of the students are $$2x, 4x, 5x, 6x, \ and \ 8x \ kg$$, then $$40 = \frac{2x + 4x + 5x + 6x + 8x}{5}$$ $$40 = \frac{25x}{5}$$ $$25x = 200$$ $$x = 8$$ then lowest weight student $$= 2x = 2 \times 8 = 16 \ kg$$

highest weight student $$= 8x = 8 \times 8 = 64 \ kg$$

1. Find the average of first six odd numbers after multiplying by $$2 \ ?$$

1. $$12$$
2. $$14$$
3. $$16$$
4. $$18$$

Answer: (a) $$12$$

Solution: $$Average = \frac{2 \ (1 + 3 + 5 + 7 + 9 + 11)}{6}$$ $$= \frac{72}{6} = 12$$

1. If there are four numbers and average of all four numbers is $$100$$ but the average of first three numbers is $$70$$, then find the fourth number?

1. $$210$$
2. $$190$$
3. $$160$$
4. $$170$$

Answer: (b) $$190$$

Solution: Sum of all four numbers = $$4 \times 100 = 400$$

sum of the first three numbers = $$3 \times 70 = 210$$

Then the fourth number = $$400 - 210 = 190$$