Percentage Aptitude Questions and Answers:


Overview:


Questions and Answers Type:MCQ (Multiple Choice Questions).
Main Topic:Quantitative Aptitude.
Quantitative Aptitude Sub-topic:Percentage Aptitude Questions and Answers.
Number of Questions:10 Questions with Solutions.

  1. If there is a couple and the income of husband is \(25 \ \%\) more than that of wife's income, then find how much percent of wife's income is less than that of husband's income?

    1. \(25 \ \%\)
    2. \(20 \ \%\)
    3. \(15 \ \%\)
    4. \(22 \ \%\)


Answer: (b) \(20 \ \%\)

Solution: Given, \(n = 25 \ \%\), then wife's income is less than that of husband's income in percent, $$ = \left(\frac{n}{100 + n} \times 100 \right) \ \% $$ $$ = \left(\frac{25}{100 + 25} \times 100 \right) \ \% $$ $$ = \left(\frac{25}{125} \times 100 \right) \ \% $$ $$ = 20 \ \% $$

  1. If the price of rice increases by \(10 \ \%\), then find how much percent of rice consumption be reduced so as not to increase the expenditure?

    1. \(9.09 \ \%\)
    2. \(8.25 \ \%\)
    3. \(9.25 \ \%\)
    4. \(8.09 \ \%\)


Answer: (a) \(9.09 \ \%\)

Solution: Given, \(n = 10 \ \%\), then the reduction in rice consumption, $$ = \left(\frac{n}{100 + n} \times 100 \right) \ \% $$ $$ = \left(\frac{10}{100 + 10} \times 100 \right) \ \% $$ $$ = \left(\frac{10}{110} \times 100 \right) \ \% $$ $$ = 9.09 \ \% $$

  1. If the price of wheat decreases by \(20 \ \%\), then find how much percent of wheat consumption be increased so as not to decrease the expenditure?

    1. \(20 \ \%\)
    2. \(28 \ \%\)
    3. \(25 \ \%\)
    4. \(30 \ \%\)


Answer: (c) \(25 \ \%\)

Solution: Given, \(n = 20 \ \%\), then the increase in wheat consumption, $$ = \left(\frac{n}{100 - n} \times 100 \right) \ \% $$ $$ = \left(\frac{20}{100 - 20} \times 100 \right) \ \% $$ $$ = \left(\frac{20}{80} \times 100 \right) \ \% $$ $$ = 25 \ \% $$

  1. If the income of Ram is \(10 \ \%\) less than that of Shyam's income, then find how much percent of Shyam's income is more than that of Ram's income?

    1. \(10.50 \ \%\)
    2. \(11.50 \ \%\)
    3. \(11.11 \ \%\)
    4. \(10.11 \ \%\)


Answer: (c) \(11.11 \ \%\)

Solution: Given, \(n = 10 \ \%\), then the Shyam's income is more than that of Ram's income in percent, $$ = \left(\frac{n}{100 - n} \times 100 \right) \ \% $$ $$ = \left(\frac{10}{100 - 10} \times 100 \right) \ \% $$ $$ = \left(\frac{10}{90} \times 100 \right) \ \% $$ $$ = 11.11 \ \% $$

  1. If the price of sugar increases \(15 \ \%\), then find how much percent of sugar comsumption be reduced so as not to increase the expenditure?

    1. \(15.043 \ \%\)
    2. \(17.042 \ \%\)
    3. \(18.042 \ \%\)
    4. \(13.043 \ \%\)


Answer: (d) \(13.043 \ \%\)

Solution: Given, \(n = 15 \ \%\), then the reduction in sugar consumption, $$ = \left(\frac{n}{100 + n} \times 100 \right) \ \% $$ $$ = \left(\frac{15}{100 + 15} \times 100 \right) \ \% $$ $$ = \left(\frac{15}{115} \times 100 \right) \ \% $$ $$ = 13.043 \ \% $$

  1. If the price of milk decreases \(5 \ \%\), then find how much percent of milk consumption be increased so as not to decrease the expenditure?

    1. \(5.26 \ \%\)
    2. \(6.25 \ \%\)
    3. \(5.05 \ \%\)
    4. \(6.05 \ \%\)


Answer: (a) \(5.26 \ \%\)

Solution: Given, \(n = 5 \ \%\), then the increase in milk consumption, $$ = \left(\frac{n}{100 - n} \times 100 \right) \ \% $$ $$ = \left(\frac{5}{100 - 5} \times 100 \right) \ \% $$ $$ = \left(\frac{5}{95} \times 100 \right) \ \% $$ $$ = 5.26 \ \% $$

  1. If the current price of a x-ray machine is \(500,000 \ Rs.\), increases \(2 \ \%\) and \(10 \ \%\) successively in two years, then find the price of x-ray machine after two years?

    1. \(565,000 \ Rs.\)
    2. \(560,000 \ Rs.\)
    3. \(561,000 \ Rs.\)
    4. \(568,000 \ Rs.\)


Answer: (c) \(561,000 \ Rs.\)

Solution: Given, \(k = 500,000 \ Rs.\), \(x = 2\), \(y = 10\), then the price of the x-ray machine after two years, $$ k \left(1 + \frac{x}{100}\right) \left(1 + \frac{y}{100}\right)$$ $$ = 500,000 \ \left(1 + \frac{2}{100}\right) \left(1 + \frac{10}{100}\right)$$ $$ = 500,000 \times \frac{51}{50} \times \frac{11}{10} = 561,000 \ Rs. $$

  1. If the weight of mohan is \(25 \ \%\) less than that of Rohan's weight, then find how much percent of Rohan's weight is more than that of Mohan's weight in percent?

    1. \(35.50 \ \%\)
    2. \(33.33 \ \%\)
    3. \(31.33 \ \%\)
    4. \(32.25 \ \%\)


Answer: (b) \(33.33 \ \%\)

Solution: Given, \(n = 25 \ \%\), then Rohan's weight is more than that of Mohan's weight in percent, $$ = \left(\frac{n}{100 - n} \times 100 \right) \ \% $$ $$ = \left(\frac{25}{100 - 25} \times 100 \right) \ \% $$ $$ = \left(\frac{25}{75} \times 100 \right) \ \% $$ $$ = 33.33 \ \% $$

  1. If the price of vegetables increases by \(2 \ \%\), then find how much percent of vegetable consumption be reduced so as not to increase the expenditure?

    1. \(1.50 \ \%\)
    2. \(2.25 \ \%\)
    3. \(2.82 \ \%\)
    4. \(1.96 \ \%\)


Answer: (d) \(1.96 \ \%\)

Solution: Given, \(n = 2 \ \%\), then the reduction in vegetable consumption, $$ = \left(\frac{n}{100 + n} \times 100 \right) \ \% $$ $$ = \left(\frac{2}{100 + 2} \times 100 \right) \ \% $$ $$ = \left(\frac{2}{102} \times 100 \right) \ \% $$ $$ = 1.96 \ \% $$

  1. If the price of water decreases by \(7 \ \%\), then find how much percent of water consumption be increased so as not to decrease the expenditure?

    1. \(8.52 \ \%\)
    2. \(7.52 \ \%\)
    3. \(7.25 \ \%\)
    4. \(8.25 \ \%\)


Answer: (b) \(7.52 \ \%\)

Solution: Given, \(n = 7 \ \%\), then the increase in water consumption, $$ = \left(\frac{n}{100 - n} \times 100 \right) \ \% $$ $$ = \left(\frac{7}{100 - 7} \times 100 \right) \ \% $$ $$ = \left(\frac{7}{93} \times 100 \right) \ \% $$ $$ = 7.52 \ \% $$